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slavikrds [6]
3 years ago
13

How is a suspension different from a colloid?

Chemistry
1 answer:
Mashcka [7]3 years ago
3 0

Answer:

Explanation:

Colloidal:

  • Colloid consist of the particles having size between 1 - 1000 nm i.e, 0.001- 1μm.  
  • The particles in colloid can not be seen through naked eye.
  • It is homogeneous.
  • We can not separate the colloidal through the filtration. The pore size of filter paper is 2μm. However it can be separated through the ultra filtration. In ultra filtration the pore size is reduced by soaking the filter paper in gelatin and then in formaldehyde. This is only in case of when solid colloidal is present, if colloid is liquid , there is no solid particles present and ultra filtration can not be used in this case.

Suspension:

  • The particle size in suspension is greater than 1000 nm.
  • These particles can seen through naked eye.
  • It is heterogeneous.  
  • The particles in suspension can be separated through the filtration.
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What is the chemical name of baking soda
abruzzese [7]

Answer:

sodium hydrogen carbonate

Explanation:

Sodium Hydrogen Carbonate

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3 years ago
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Calculate the molecular weight when a gas at 25.0 ∘C and 752 mmHg has a density of 1.053 g/L . Express your answer using three s
stiks02 [169]

Answer:

26.0 g/mol is the molar mass of the gas

Explanation:

We have to combine density data with the Ideal Gases Law equation to solve this:

P . V = n . R .T

Let's convert the pressure mmHg to atm by a rule of three:

760 mmHg ____ 1 atm

752 mmHg ____ (752 . 1)/760 =  0.989 atm

In density we know that 1 L, occupies 1.053 grams of gas, but we don't know the moles.

Moles = Mass / molar mass.

We can replace density data as this in the equation:

0.989 atm . 1L = (1.053 g / x ) . 0.082 L.atm/mol.K . 298K

(0.989 atm . 1L) / (0.082 L.atm/mol.K . 298K) = 1.053 g / x

0.0405 mol = 1.053 g / x

x =  1.053 g / 0.0405  mol = 26 g/mol

7 0
4 years ago
Why does the amount of energy available change as you move from one trophic level to the next?
olga_2 [115]

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3 years ago
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What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? Ass
jeyben [28]

Answer : The net ionic equation will be,

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : It is defined as the ions present on reactant and product side that do not participate in the reactions. That means the same ions present on both the sides.

The given balanced ionic equation will be,

BaSO_4(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+H_2O(aq)

The ionic equation in separated aqueous solution will be,

Ba^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)+2H^+(aq)+2OH^-(aq)

In this equation, H^+\text{ and }OH^- ions are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

8 0
3 years ago
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I think that is the short answer, if not I apologize. Have a wonderful day! :)

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