Using your knowledge of reactions and mechanisms, draw the mechanism for the formation of 2-methylpropene from 2-methyl-2-propan
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1 answer:
Answer:
Here's what I get
Explanation:
The reaction is an E1 elimination of an alcohol to form an alkene. It has three steps:
1. Protonation
The alcohol is protonated with aqueous sulfuric acid to convert it into a better leaving group.
2. Loss of the leaving group
A water molecule leaves in a unimolecular process to form a stable 3° carbocation.
3. Loss of an α-hydrogen
A water molecule removes an α-hydrogen, forming 2-methylpropene and regenerating the original hydronium ion.
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Explanation:
It is known that molality is the number of moles present in kg of solution.
Mathematically, Molality =
The given data is as follows.
Molar mass of ammonia = 17 g/mol
Concentration = 1.002 mg/L =
= mol/L
Also, density = = 1 kg/L
Therefore, molality will be calculated as follows.
Molality =
=
And,
Molar mass of nitrite = 46 g/mol
Concentration = 0.387 mg/L =
= mol/L
And, density = = 1 kg/L
Hence, molality =
= mol/kg
Now, Molar mass of nitarte = 62 g/mol
Concentration = 1352.2 mg/L
=
= 0.02181 mol/L
Also, density = = 1 kg/L
Hence, molality will be calculated as follows.
Molality =
= 0.02181 mol/kg
Therefore, molality of given species is for ammonia,
mol/kg for nitrite, and 0.02181 mol/kg for nitrate ion.