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2 years ago

Angle D in EDF is a right angle. What is the value of tan F? Click on the photo

Mathematics

2 answers:

Anit [1.1K]2 years ago

4 0

tan F = opposite/base = 4/3

so answer is option a

Lady_Fox [76]2 years ago

4 0

Answer:

a) 4/3

Step-by-step explanation:

The ratio of tangent is opposite/adjacent.

For angle F, the side opposite has length 4. The side adjacent angle F has length 3. This makes

tan F = opposite/adjacent = 4/3.

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How do u do this please help!!

aev [14]

Answer:

Step-by-step explanation:

1 gallon = 4 quarts

5 gallons 2 quarts 1 pint = 4 gallons 6 quarts 1 pint

(5 gallons 2 quarts 1 pint) - (1 gallon 3 quarts)

= (4 gallons 6 quarts 1 pint) - (1 gallon 3 quarts)

= 3 gallons 3 quarts 1 pint

7 0

3 years ago

Solve dis attachment and show all work ( I got it all wrong and I want to know how to solve it )

DedPeter [7]

(a) First find the intersections of $y=e^{2x-x^2}$ and $y=2$ :

$2=e^{2x-x^2}\implies \ln2=2x-x^2\implies x=1\pm\sqrt{1-\ln2}$

So the area of $R$ is given by

$\displaystyle\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\left(e^{2x-x^2}-2\right)\,\mathrm dx$

If you're not familiar with the error function $\mathrm{erf}(x)$ , then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.

(b) Find the intersections of the line $y=1$ with $y=e^{2x-x^2}$ .

$1=e^{2x-x^2}\implies 0=2x-x^2\implies x=0,x=2$

So the area of $S$ is given by

$\displaystyle\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}(2-1)\,\mathrm dx+\int_{1+\sqrt{1-\ln2}}^2\left(e^{2x-x^2}-1\right)\,\mathrm dx$
$\displaystyle=2\int_0^{1-\sqrt{1-\ln2}}\left(e^{2x-x^2}-1\right)\,\mathrm dx+\int_{1-\sqrt{1-\ln2}}^{1+\sqrt{1-\ln2}}\mathrm dx$

which is approximately 1.546.

(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve $y=e^{2x-x^2}$ and the line $y=1$ , or $e^{2x-x^2}-1$ . The area of any such circle is $\pi$ times the square of its radius. Since the curve intersects the axis of revolution at $x=0$ and $x=2$ , the volume would be given by

$\displaystyle\pi\int_0^2\left(e^{2x-x^2}-1\right)^2\,\mathrm dx$

5 0

3 years ago

Evaluate: 11 + sqrt(-4 + 6×4÷3)

Murrr4er [49]

Answer:

$11+\frac{2\sqrt{15}}{3}$

Step-by-step explanation:

$11 + \sqrt{(-4 + 6\times4\div3)} \\\\11+\sqrt{\frac{-4+6\times \:4}{3}}\\\\\sqrt{\frac{-4+6\times \:4}{3}}=\frac{2\sqrt{5}}{\sqrt{3}}\\\\=11+\frac{2\sqrt{5}}{\sqrt{3}}\\\\\frac{2\sqrt{5}}{\sqrt{3}}=\frac{2\sqrt{15}}{3}\\\\=11+\frac{2\sqrt{15}}{3}$

3 0

2 years ago

Explain why graphing the solutions of an inequality is more efficient than listing all the solutions of the inequality.

Nadya [2.5K]

The saying "A picture is worth a thousand words" comes to mind here. You can list all of the possible points in a solution region, or you can list a few points to give the general pattern. Though this method requires a bit more work than simply graphing and showing the solution shaded region. A visual is often more efficient at conveying a message especially to those who aren't proficient with algebra. I'm sure there are other reasons why graphs are the better choice, but that's all I could think of really.

6 0

2 years ago

Read 2 more answers

Maria says that the store can hold about 180 cans. She shows her work as follows. First,20x5=180 100 Next,20x4=80 then,100+80=18

nevsk [136]

Maria is correct according to the problem

3 0

3 years ago