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3 years ago

In 8 years tamika will be 22 how old is she now?

Mathematics

2 answers:

aleksandrvk [35]3 years ago

6 0

Answer:

Step-by-step explanation:

22-8=14

Nataly_w [17]3 years ago

6 0

Answer:

shes 14

Step-by-step explanation:

22-8

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Whenever 2 line or intersect at 90 the 2 lines are said to be ?

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Two lines that intersect at 90 degrees are considered perpendicular to each other.

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For what interval is the function f(x) = (20 + \sqrt{x}) / (\sqrt{20 + x}) continuous?

konstantin123 [22]

Try this solution:
1. according to the condition
$\left \{ {{x \geq 0} \atop {20+x\ \textgreater \ 0}} \right. \ =\ \textgreater \ \ x \geq 0.$
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2 years ago

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zheka24 [161]

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Before: 8 tons

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3 years ago

What is the coefficient and constant of 3c + 4

kobusy [5.1K]

Answer:

The coefficient is 3 and the constant is 4 in

relation to the equation mx + c where m is the coefficient of x and c is the constant.

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3 years ago

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Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

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3 years ago