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yan [13]
3 years ago
14

The equation above can be used to calculate the volume V, of a cone with a height h and radius r. If the volume of a cone is 243

?ft3, and the height is equal to the radius of the base, what is the height of the cone in feet?
Mathematics
1 answer:
WARRIOR [948]3 years ago
5 0

Answer:

The height of the cone is h=9\ ft

Step-by-step explanation:

we know that

The volume of a cone is equal to

V=\frac{1}{3}\pi r^{2}h

In this problem we have

V=243\pi\ ft^{3}

r=h\ ft

substitute

243\pi=\frac{1}{3}\pi (h^{2})h

simplify

729=(h^{3})

h=\sqrt[3]{729}\ ft

h=9\ ft

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aleksklad [387]

Answer:

b. There is a 95% chance that the true proportion of teenagers who use Mybook as their primary social network site is in the interval (0.2964, 0.9036).

Step-by-step explanation:

Hello!

In general, a 95% confidence interval for the population proportion can be interpreted as: There is a 95% chance (or confidence) that the interval will contain the true value of the proportion.

(Remember the confidence level of 95% means that if you were to make 100 intervals for the population proportion, 95 of them will contain its true value)

The estimated parameter is the population proportion of teenagers that use Mybook as their primary social network site.

With this in mind then you can say that there is a 95% probability that the interval (0.2964, 0.9036) will contain the true value of the proportion of teenagers that use Mybook as their primary social network site.

The correct answer is: b

I hope this helps!

8 0
3 years ago
What is (-6) to the negative 5 exponent over 3 to the negative 2 exponent?
loris [4]

Answer:

\displaystyle -\frac{1}{864}

Step-by-step explanation:

\displaystyle \frac{-6^{-5}}{3^{-2}} = \frac{-\frac{1}{7776}}{\frac{1}{9}} = -\frac{1}{864}

8 0
3 years ago
An oil-drilling rig has dug a hole to a depth of -60 ft. after one full day and night of continuous
lesantik [10]

Answer:

It will take 60 hrs

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3 0
3 years ago
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What is the gcf of 28x^3 and 16x^2 y^2
alexdok [17]
There not a answer for that
8 0
3 years ago
(sinx + icosx)^n = cos( nπ\2 - nx) + isin( nπ\2 - nx)
Alenkasestr [34]
\sin x+i\cos x=i(\cos x-i\sin x)=ie^{-ix}=e^{i\frac\pi2}e^{-ix}=e^{i\left(\frac\pi2-x\right)}

By DeMoivre's theorem,

(\cos y+i\sin y)^n=(e^{iy})^n=e^{iny}=\cos(ny)+i\sin(ny)

which would here mean that

(\sin x+i\cos x)^n=\left(e^{i\left(\frac\pi2-x\right)}\right)^n=e^{i\left(\frac{n\pi}2-nx\right)}=\cos\left(\dfrac{n\pi}2-nx\right)+i\sin\left(\dfrac{n\pi}2-nx\right)

as required.
5 0
3 years ago
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