Answer:
solution below
Step-by-step explanation:
The question says 6 working mother's were selected so <u>n = 6</u><u> </u><u>not</u><u> </u><u>0</u><u>.</u><u>6</u>
We are expected to find
P(X = 0,1,2,3,4,4,6)
1. <u>When x = 0</u>
6C0*(0.34)⁰*(0.66)⁶
= 1 *1* 0.827
= 0.0827
<u>2. When X = 1</u>
6C1*(0.34)¹*(0.66)⁵
= 6 x 0.34 x 0.252
= 0.2555
<u>3. When X = 2</u>
6C2*(0.34)²*(0.66)⁴
= 15 x 0.1156 x 0.1897
= 0.3289
<u>4. When x = 3</u>
6C3*(0.34)³*(0.66)³
20 x 0.039304 x 0.2875
= 0.2599
<u>5. When X = 4</u>
6C4*(0.34)⁴*(0.66)²
= 15 x 0.01336 x 0.4356
= 0.8729
<u>6. When x = 5</u>
6C5*(0.34)⁵*(0.66)¹
= 6 x 0.0045 x 0.66
= 0.01782
<u>7. When x = 6</u>
6C6*(0.34)⁶*(0.66)⁰
1 x 0.0015 x 1
= 0.0015
Answer:
The first five terms in Pattern B are 3, 7, 11, 15, 19.
Step-by-step explanation:
Answer:
32
Step-by-step explanation:
i don't know if its right but i did 704 divided by 22 which equals to 22
If there is nothing missing in your question, the answer is :
0.5y - 10x
