
- Given - <u>an </u><u>equation</u><u> </u><u>in </u><u>a </u><u>standard</u><u> </u><u>form</u>
- To do - <u>simplify</u><u> </u><u>the </u><u>equation</u><u> </u><u>so </u><u>as </u><u>to </u><u>obtain </u><u>an </u><u>easier </u><u>one</u>
<u>Since </u><u>the </u><u>equation</u><u> </u><u>provided </u><u>isn't</u><u> </u><u>i</u><u>n</u><u> </u><u>it's</u><u> </u><u>general</u><u> </u><u>form </u><u>,</u><u> </u><u>let's</u><u> </u><u>first </u><u>convert </u><u>it </u><u>~</u>
<u>General</u><u> </u><u>form </u><u>of </u><u>a </u><u>Linear</u><u> equation</u><u> </u><u>-</u>

<u>T</u><u>he </u><u>equation</u><u> </u><u>after </u><u>getting</u><u> </u><u>converted</u><u> </u><u>will </u><u>be </u><u>as </u><u>follows</u><u> </u><u>~</u>

hope helpful ~
Answer:
x= 88
Step-by-step explanation:
Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
Answer:
-74
Step-by-step explanation:
Graph the function. See attached picture. Between the interval where -4 > x < 0, the graph rises up to a peak and descends back down when x = 0. This means the minimum value will be where x = -4.
Substitute x = -4 into the equation.
f(-4) = (-4)^3 -3(-4)^2 - 9(-4) + 2
f(-4) = -64 -3(16) +36 + 2
f(-4) = -64 - 48 + 36 + 2
f(-4) = -74
D is correct because it is a tenth and it becomes a hundredth