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lukranit [14]
3 years ago
15

Why must the ph ammonia buffer solution be stored and dispensed in the fume exhaust hood?

Chemistry
1 answer:
Vadim26 [7]3 years ago
7 0

On the other hand ammonia is a very dangerous chemical which has a pungent smell and effect the eyes of the user. Thus it kept always in the fume exhaust hood for storing and dispensing function.  

The  pH of ammonia buffer contains ammonium hydroxide (NH₄OH) and a salt of ammonia with a  strong acid like (HCl) which produces, ammonium chloride (NH₄Cl) mixture. The evaporation rate of ammonia is so high at room temperature thus on opening of the buffer solution the ammonia get evaporated very fast and the concentration of ammonia decreases which affect the pH of the buffer solution.

Thus the reason to put ammonia buffer in fume hood is explained.


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naturally as mixtures of two abundant isotopes. Chlorine occurs as 35Cl (75.8%) and 37Cl (24.2%); Bromine occurs as 79Br (50.7%)
anyanavicka [17]

Answer:

Masses of bromobenzene molecular ions will occur at 156 and 158 m/z.

Explanation:

The molecular ion peak is the signal in the mass spectrum of a compound that represents the molecular ion (denoted as M). Compounds that are composed of atoms having abundant isotope also shows M +1 and M+2 peaks (depending on the isotope).

In the given bromobenzene compound, an atom of bromine is present. The two isotopes with considerable relative abundance of Br are 79Br and 81Br with a difference of two units in their mass. This means that two molecular ion peaks with a difference of two units will appear in the mass spectrum. The mass of the whole compound is 156 amu. Hence, the molecular ion peaks will appear at 156 m/z and 158 m/z due to the two isotopes of bromine.

6 0
3 years ago
Which of the following is NOT a unit of energy?
kap26 [50]

Answer:

Degree Celsius

8 0
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Where will you find maximum rate of evaporation ocean,pond
Natalka [10]
Oceans, they are larger than ponds hence they possess wider exposure with more number of surface molecules. 
6 0
3 years ago
A 10-kg object is pushed across a rough surface. It begins at rest and accelerates to a speed of 4 m/s in a distance of 5m. Whic
Lynna [10]

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4 0
4 years ago
Determine the empirical formula for compounds that have the following analyses: a. 66.0% barium and 34.0% chlorine b. 80.38% bis
almond37 [142]

Answer: a) BaCl_2

b)  BiO_3H_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

a) Mass of Ba= 66.06 g

Mass of Cl = 34.0 g

Step 1 : convert given masses into moles.

Moles of Ba =\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{66.06g}{137g/mole}=0.48moles

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ba = \frac{0.48}{0.48}=1

For O =\frac{0.96}{0.48}=2

The ratio of Ba: Cl= 1:2

Hence the empirical formula is BaCl_2

b) Mass of Bi= 80.38 g

Mass of O= 18.46 g

Mass of H = 1.16 g

Step 1 : convert given masses into moles.

Moles of Bi =\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{80.38g}{209g/mole}=0.38moles

Moles of O= \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{18.46g}{16g/mole}=1.15moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.16g}{1g/mole}=1.16moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Bi= \frac{0.38}{0.38}=1

For O =\frac{1.15}{0.38}=3

For H=\frac{1.16}{0.38}=3

The ratio of Bi: O: H= 1:3: 3

Hence the empirical formula is BiO_3H_3

6 0
3 years ago
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