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3 years ago

How many protons, neutrons, and electrons are in Ca-44?

Chemistry

1 answer:

Mariulka [41]3 years ago

4 0

Protons = 20
Electron = 20
Neutrons = 20
Hope this Helps :)

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Calculate the molarity of kcl in the solution if the total volume of the solution is 239 ml.

Akimi4 [234]

When concentration is expressed in molarity, this is equivalent to the number of moles of the solute per liter of solution. We are given with the amount of volume which is 239 mL or 0.239 L. However, there is no known information of the amount of solute. So, I can't give an exact answer. For sample purposes, let's just assume that there is 1 mole of KCl in the solution. The molarity would be:

Molarity = 1 moles/0.239 L = 4.184 M

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4 years ago

Highly liquid lava forms wide, shield-like mountains. True False

timurjin [86]

This answer is True :)

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3 years ago

Which of the following types of radiation can penetrate the most deeply into your body?

ivolga24 [154]

Answer:

gamma rays

Explanation:

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4 years ago

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3 years ago

El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si

Alchen [17]

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

$PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)$

Lo cual hace que la expresión de equilibrio se calcule como:

$Ksp=[Pb^{2+}][Cl^-]^2$

Y que en términos de la solubilidad molar, s, se resuelve como:

$1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L$

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

$s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L$

¡Saludos!

7 0

3 years ago