Answer:
C. A hydrocarbon molecule containing six carbon atoms and only
single bonds
Explanation:
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Answer:
The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.
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Answer : The solubility of a gas in water at 1 atm pressure is, 0.4436 g/L
Solution : Given,
Solubility of a gas in water = 1.22 g/L (at 2.75 atm pressure)
At pressure = 1 atm, Solubility of a gas = ?
Now we have to calculate the solubility of a gas.
At 2.75 atm pressure, the solubility of a gas in water = 1.22 g/L
At 1 atm pressure, the solubility of a gas in water = 
Therefore, the solubility of a gas in water at 1 atm pressure is, 0.4436 g/L
The answer is B hope this is right
Answer:
Accelerate, Have Constant velocity, Velocity, and First
Explanation:
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