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vlada-n [284]
3 years ago
7

Pick 1 answer, please help!

Chemistry
2 answers:
nasty-shy [4]3 years ago
4 0
The the answer is: C
Alexeev081 [22]3 years ago
3 0
The correct answer is option c
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If you compare the egg to a cell, what did you learn about how water moves into or out of a cell
sleet_krkn [62]

If we compare a cell with an egg there is a major difference between the outer membrane

in case of cell they are bounded by semi permeable membrane  

The semi permeable membrane is a selectively permeable membrane which allows the movement of only solvent molecule and not solute molecules through it.

So water can move into or out of the cell through cell membrane by a special physical process known as osmosis.  

the water will move from a low concentration gradient to high concentration gradient.

4 0
4 years ago
A compound contains 6.0 g of carbon and 1.0 g of hydrogen and has a molar mass of 42.0 g/mol.
makvit [3.9K]

Answer:

%C = 85.71 wt%; %H = 14.29 wt%; Empirical Formula => CH₂; Molecular Formula => C₃H₆

Explanation:

%Composition

Wt C = 6 g

Wt H = 1 g

TTL Wt = 6g + 1g = 7g

%C per 100wt = (6/7)100% = 85.71 wt%

%H per 100wt = (1/7)100% = 14.29 wt % or, %H = 100% - %C = 100% - 85.71% = 14.29 wt% H

What you should know when working empirical formula and molecular formula problems.

Empirical Formula=> <u>smallest</u> whole number ratio of elements in a compound

Molecular Formula => <u>actual</u> whole number ratio of elements in a compound

Empirical Formula Weight x Whole Number Multiple = Molecular Weight

From elemental %composition values given (or, determined as above), the empirical formula type problem follows a very repeatable pattern. This is ...

% => grams => moles => ratio => reduce ratio => empirical ratio

for determination of molecular formula one uses the empirical weight - molecular weight relationship above to determine the whole number multiple for the molecular ratios.

Caution => In some 'textbook' empirical formula problems, the empirical ratio may contain a fraction in the amount of 0.25, 0.50 or 0.75. If such an issue arises, multiply all empirical ratio numbers containing 0.25 and/or 0.75 by '4'  to get the empirical ratio and multiply all empirical ration numbers containing 0.50 by '2' to get the final empirical ratio.

This problem:

Empirical Formula:

Using the % per 100wt values in part 'a' ...

              %     =>         grams                 =>                 moles

%C => 85.71% => 85.71 g* / 100 g Cpd => (85.71 / 12) = 7.14 mol C

%H => 14.29% => 14.29 g / 100 g Cpd => (14.29 / 1) = 14.29 mol H

=> Set up mole Ratio and Reduce to Empirical Ratio:

mole ratio C:H =>  7.14 : 14.29

<u>To reduce mole values to the smallest whole number ratio,  divide all mole values by the smaller mole value of the set.</u>

=> 7.14/7.14 : 14.29/7.14 => Empirical Ration=> 1 : 2

∴ Empirical Formula => CH₂

Molecular Formula:

(Empirical Formula Wt)·N = Molecular Wt => N = Molecular Wt / Empirical Wt

N = 42 / 14 = 3 => multiply subscripts of empirical formula by '3'.

Therefore, the molecular formula is C₃H₆

3 0
3 years ago
Based on the kinetic theory, which statement is true? (5 points)
Hoochie [10]

Answer:

the particles of matter are arranged in different ways for the different states

Explanation:

because solid liquid and gas all three matters have different states for example the particles in a solid are closely packEd and form of movement is vibration

7 0
2 years ago
Which properties represent a metal ( select all that apply )
blagie [28]

Malleable, shiny and good conductors
A B E
4 0
3 years ago
Biphenyl and benzene are common side products in this gringard reaction. explain at which points in the purification procedure t
mafiozo [28]

In Grignard reaction, Biphenyl and benzene are common side products which are removed during trituration.

In organic chemistry, a reaction in which the Grignard reagents or organometallic substances are added to organic compounds such as aldehydes and ketones to form alcohol is known as Grignard reaction.

These Grignard reagents are magnesium halides of alkyl, vinyl or allyl, which react with a carbonyl group to form alcohols.

During this reaction, primary, secondary and tertiary alcohols are formed.

While Biphenyl and benzene are common side products.

These are removed during trituration process in which cold petroleum ether is added to dissolve the biphenyl and benzene side products

If you need to learn more about Biphenyl and benzene click here:

brainly.com/question/4336669

4 0
2 years ago
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