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Sergio039 [100]
3 years ago
7

You are given three white​ balls, one red​ ball, and two identical boxes. You are asked to distribute the balls in the boxes in

any way you like. You then are asked to select a box​ (after the boxes have been​ shuffled) and to pick a ball at random from that box. If the ball is red you win a prize. How should you distribute the balls in the boxes to maximize your chances of​ winning? Justify your reasoning.
Mathematics
1 answer:
Colt1911 [192]3 years ago
5 0
Put all the white balls in one box and the red ball in the other so you have a 50% chance of winning if you put 1 red ball and a white now you have a 25% chance cause you have a 50% chance in choosing the right box then you have to chose the right ball which would be 50%
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The probability that less than 800 students who said they still had their original major is 0.50 or 50%.

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Let the random variable <em>X</em> be described as the number of third-year college students if they still had their original major.

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The random variable <em>X </em>thus follows Binomial distribution with parameters n = 1600 and p = 0.50.

X\sim Bin(1600, 0.50)

As the sample size is large, i.e.<em>n</em> > 30, and the probability of success is closer to 0.50,  Normal approximation can be used to approximate the binomial distribution.

The mean of <em>X</em> is:

\mu_{x}=np=1600\times0.50=800\\

The standard deviation of <em>X</em> is:

\sigma_{x}=\sqrt{np(1-p}=\sqrt{1600\times0.50(1-0.50)}=20

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