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Sergio039 [100]
3 years ago
7

You are given three white​ balls, one red​ ball, and two identical boxes. You are asked to distribute the balls in the boxes in

any way you like. You then are asked to select a box​ (after the boxes have been​ shuffled) and to pick a ball at random from that box. If the ball is red you win a prize. How should you distribute the balls in the boxes to maximize your chances of​ winning? Justify your reasoning.
Mathematics
1 answer:
Colt1911 [192]3 years ago
5 0
Put all the white balls in one box and the red ball in the other so you have a 50% chance of winning if you put 1 red ball and a white now you have a 25% chance cause you have a 50% chance in choosing the right box then you have to chose the right ball which would be 50%
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6 more than a number is at most 10.<------Put as an inequality.The sum of a number and 14 is at least 18<----Put as an ine
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X+6 less than or equal to 10 
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6 0
2 years ago
If AB=BC,AB=4=4x-2,andBC=3x+3,fine the length of AB
laila [671]

Answer:

18

Step-by-step explanation:

First, I'm assuming AB=4=4x-2 was a typo and it's supposed to be AB = 4x - 2

AB=BC

AB = 4x - 2 BC = 3x + 3

4x - 2 = 3x + 3

Solve for x Add 2 to each side

4x - 2 = 3x + 3

4x - 2 + 2 = 3x + 3 + 2

4x = 3x + 5 Subtract 3x from each side.

4x - 3x = 3x- 3x + 5

4x - 3x = 5

x = 5

Now plug back in to the original equations

AB = 4x - 2                  BC = 3x + 3

AB = 4 (5) - 2               BC = 3(5) + 3

AB = 20 - 2                  BC = 15 + 3

AB = 18                        BC = 18

So AB is 18

3 0
3 years ago
Solve the following by elimination method <br> 11x+15y+23=0 and 7x-2y-20=0
mr Goodwill [35]
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
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127x = 254
x = 254/127
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Substitute x = 2 in equation (1) to find y:
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15y = -45
y = -45/15
y = -3

Therefore, x = 2 and y = -3.
7 0
3 years ago
What type of quadrilateral has to the vertices A(3,6), B(3,3), C(6,3), and D(6,6)
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a square as the distance between the lengths and widths are 3

8 0
3 years ago
Helen bought notebooks and pencils for school. The number of pencils she bought is given by 6(n-3) , where n is the number of no
pychu [463]
So the number of pencils bought can be represented by an equation: P=6(n-3), where n is the number of notebooks bought. Since Helen bought 5 notebooks, simply plug 5 into n: P=6(5-3)=6(2)=12. So Helen bought 12 pencils.
3 0
3 years ago
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