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Sergio039 [100]
3 years ago
7

You are given three white​ balls, one red​ ball, and two identical boxes. You are asked to distribute the balls in the boxes in

any way you like. You then are asked to select a box​ (after the boxes have been​ shuffled) and to pick a ball at random from that box. If the ball is red you win a prize. How should you distribute the balls in the boxes to maximize your chances of​ winning? Justify your reasoning.
Mathematics
1 answer:
Colt1911 [192]3 years ago
5 0
Put all the white balls in one box and the red ball in the other so you have a 50% chance of winning if you put 1 red ball and a white now you have a 25% chance cause you have a 50% chance in choosing the right box then you have to chose the right ball which would be 50%
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A lock has a code of 3 numbers between 1 and 25. If no numbers in the code are allowed to repeat, how many different codes could
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12167 codes can be made
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2 years ago
10. Write an equation of your own that has no solution. Transform the equation to demonstrate that it has no solution
wolverine [178]
4(x+5)+6=2(2x+3)
4x+20+6=4x+6
4x+26=4x+6
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26=6 
no solution because 26 does not equal 6
4 0
3 years ago
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Angie bought a shirt that was priced at 16.50.She paid 18.82 at the counter . what is the tax rate. Step by step
erastovalidia [21]

Answer:

The price: 16.5

The total payment: 18.82

=> The amount of tax: 18.82-16.5 = 2.32

=> Tax rate = The amount of tax / The price = 2.32/16.5 = 0.14 = 14%

6 0
2 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Kim has a lawn service business. The equation 165 – 105x + 3y = 0 relates y, her weekly profits , and 2, the number of lawns she
Ede4ka [16]

Answer:

1. -105

2. 3

3. 165

1. -35

2. 55

3. y= mx + b

= -105 + 0

= -105

4 0
3 years ago
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