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AysviL [449]
3 years ago
9

Simplify Rewrite the expression in the form 5 ^ n. (5/10)/(5/12) =

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0

Answer:

5^{-2}

Step-by-step explanation:

5^{(10-12)}

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Nesterboy [21]
B and d are correct
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2 years ago
27 (x2+8x+16) / 3 (x2+6x+8) simplify
Karolina [17]

Answer:

9x4+126x3+648x2+1440x+1152


Step by step:

27(x^2+8x+16) / 3 (x^2+6x+8)

(27(x^2+8x+16) / 3) (x^2+6x+8)

(27(x^2+8x+16) / 3) (x^2) +(27(x2+8x+16) / 3) (6x)+(27(x2+8x+16)/3) (8)

9x4+72x^3+144x^2+54x^3+432x^2+864x+72x^2+576x+1152


9x4+126x3+648x2+1440x+1152


3 0
3 years ago
The population of Philadelphia in 1990 was 1,585,577. In 2010 the population was 1,526,006. What is the percent change the popul
UNO [17]

Answer:

-3.9% I.e there is decrease in the population

Step-by-step explanation:

Population @ 1990 = 1585577

Population @ 2010 = 1526006

% change =

(1526006-1585577)/1526006 × 100%

= -59571/1526006 ×100%

= -3.9%

7 0
3 years ago
Use the graphing calculator to
Leviafan [203]

Answer:

Step-by-step explanation:

Answer is C: x-min = 0, x-max= 30, y-min = 0, y-max = 30

5 0
3 years ago
Read 2 more answers
A colony contains 1500 bacteria. The population increases at a rate of 115% each hour. If x represents the number of hours elaps
Burka [1]

Answer:Answer:

Option (c) is correct.

function representing the increase of bacteria every hour x,

Step-by-step explanation:

Given : A colony contains 1500 bacteria. The population increases at a rate of 115% each hour.

we have to find the function that represents the given scenario.

Let x represents the number of hours elapsed.

Given  A colony contains 1500 bacteria

and number of bacteria is increasing at a rate of 115% each hour.

Using formula for Compound interest , we have,

Where A is amount

T is time period

R is rate of interest

Here, P = 1500

T = x hours

R = 115%

Let f(x) be the function representing the increase of bacteria every hour.

Substitute, we have,

Simplify, we get,

Thus,  function representing the increase of bacteria every hour x,

5 0
3 years ago
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