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AysviL [449]
3 years ago
9

Simplify Rewrite the expression in the form 5 ^ n. (5/10)/(5/12) =

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
5 0

Answer:

5^{-2}

Step-by-step explanation:

5^{(10-12)}

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Please help @Nopinkiepie and @Oretummy
zubka84 [21]
Easy peasy
the fastest way is to pretend we have 1 big rectangle with  2 smaller rectangles cut out
see attachment

the big one is 12 by 7
the smaller ones are 5 by6 and 5 by 6

big-smaller=area
big=12*7=84
smaller=5*6+5*6=30+30=60

big-smaller=84-60=24


answer is 24 in²

first choice

3 0
3 years ago
I need the answer pls answer fast
son4ous [18]

Answer:

A = 846 in²

Step-by-step explanation:

The area (A) of a rhombus is calculated as

A = \frac{1}{2} × d₁ × d₂ ( d₁ and d₂ are the diagonals ) , then

A = \frac{1}{2} × 36 × 47 = 18 × 47 = 846 in²

7 0
3 years ago
Read 2 more answers
What is the answer for 5x1+2?<br> I
tekilochka [14]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
Find the length of diagonal HJ. Round to the nearest hundredth.
Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ x_{1}=-4 and x_{2}=5

∴ y_{1}=3 and y_{2}=-3

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

∴ HJ = \sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0
3 years ago
282736.2816×296.092÷2917=?
Gnom [1K]

Answer:

28699.3318792

Step-by-step explanation:

4 0
3 years ago
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