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AVprozaik [17]
3 years ago
15

A man has 108 ft. of fencing to put around a rectangular garden. If the length is 5 times the width, find the dimensions of his

garden.
Mathematics
1 answer:
wlad13 [49]3 years ago
3 0
108 is perimeter
5x +x + 5x +x
108=12x
X=9

Dimensions are 45 ft by 9ft
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When Frank buys three packs of pens, he knows he has 36 pens. When he buys five packs, he knows he has 60 pens. What is the cons
jenyasd209 [6]

Answer:

Loggerhead turtles live and migrate around the Atlantic Ocean. Which of the following is an adaptation of Loggerhead turtles? *

Step-by-step explanation:

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7 0
3 years ago
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[(7+3)x5-4](divided by) 2+3<br> SHOW ALL WORK WILL MARK BRAINLIEST
Nesterboy [21]

Answer:

26

Step-by-step explanation:

[(7+3)5-4]/2+3

-To solve this equation you have to use PEMDAS

P- Parentheses

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction-

- With MD and AS you work left to right of the equation since they are in the same spot. (PE[MD][AS])

Step 1) [(10)5-4]/2+3

- First you do "P," parentheses, so you add 7+3=10

Step 2) [50-4]/2+3

- Next you do "M," multiplication, and multiply 10x5=50

Step 3) [46]/2+3

- Then you do "S," subtraction, and subtract 50-4=46

(FYI: Steps 1-3 were still in the parentheses. We had to start with the parentheses in the parentheses, work PEMDAS, and now we are out of the parentheses and have to work PEMDAS on the rest of the problem.)

Step 4) 23+3

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(FYI: "/" means division)

4 0
2 years ago
Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the
motikmotik

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

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Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0
3 years ago
How do you substitute 4(x) into the inequality 1/2x+5y-10&lt;0 to find the possible value of y?
Veseljchak [2.6K]
You put 4 in the X
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3 years ago
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MAXImum [283]

Answer:

Texting speed

Step-by-step explanation:

It's the dependent variable

5 0
3 years ago
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