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DochEvi [55]
3 years ago
10

A frame contains 4 pounds of gold. Suppose gold is worth $1,277 per ounce. How much would the gold in the crown be worth? $5,108

$20,432 $40,864 $81,728
Mathematics
2 answers:
Ahat [919]3 years ago
7 0

Answer:

$81,728

Step-by-step explanation:

There are 16 ounces in a pound there for you would take $1,277 and multiply it by 16 which would give you $20,432 per pound. Next you would multiply $20,432 by 4 since there are 4 pounds which would give you $81,728.

Art [367]3 years ago
4 0

Answer:

5108

Step-by-step explanation:

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4 years ago
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
What is the equation of the line that passes through the point (3,-7) and has a slope of -4/3?
Gemiola [76]

Answer:

4x + 3y + 9 = 0

Step-by-step explanation:

When a slope of a line and a point passing through it is given then we use slope - one point form to determine the equation of the line.

It is given by:

                      $ (y - y_1) = m (x - x_1) $

where $m$ is the slope of the line and

           $ (x_1, y_1) $ is the point passing through it.

Here, $ m = \frac{-4}{3} $ and $ (x_1 , y_1) = (3 , -7) $.

Substituting in the formula y +  7 = \frac{-4}{3} (x - 3)

$ \implies 3y + 21 = -4x + 12 $

$ 4x + 3y + 9 = 0 $

3 0
3 years ago
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