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3241004551 [841]
3 years ago
11

PLEASE HELP How far is x from 5 on a number line?

Mathematics
1 answer:
Digiron [165]3 years ago
3 0

Answer:

Depends on what x is

Step-by-step explanation:

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Your sock drawer has two white socks, four brown socks, and two black socks. You randomly pick a sock and put it on your left fo
zmey [24]

Answer:

The probability of this occurring is 1/7

Step-by-step explanation:

Okay, here is a probability question.

From the question, we can identify the following;

Total number of socks = 2 + 4 + 2 = 8 socks

Since we are not given the order in which the socks was worn, we can assume any order.

Let’s say the right leg socks was worn first.

From the question, the socks on the right leg is a brown one.

So now let’s calculate the probability of selecting a brown socks out of the mix

That would be ;

number of brown socks/ total number of socks = 4/8 = 1/2

Now, for the left foot, we are having white sock here.

Kindly recall that since we already have a sock on the right foot, we have 7 socks left to pick from.

Now we need the probability of picking a white sock from the total 7. That would be ; 2/7

So the probability of both action occurring is simply the product of both probabilities and that is ;

1/2 * 2/7 = 1/7

6 0
3 years ago
A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.​
Papessa [141]

<u>Answer:</u>

\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}

\bf \implies n_{cubes} = \dfrac{20cm \times  6cm \times 4cm .}{2cm  \times 2cm  \times 2cm } \\\\\bf\implies n_{cubes}  = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }

<h3><u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>

6 0
3 years ago
PLEASE HELP!!! I WILL GIVE BRAINY!!!
11111nata11111 [884]
The first one is 4/3

We can solve by,

{x}^{2} \times 180 = 320

x = \frac{4}{3}

{ \frac{4}{3} }^{2} \times 180 = 320 = true

~~

The second one is 35.

Idk how to explain...

~~

The third one is a 6 - gon therefore cannot be C or D.

I'd say the third one is A., it looks like it's caving in.
4 0
2 years ago
Read 2 more answers
Let f(x)= 12/4x+2 find f(-1)
denis23 [38]
F(x) = 12/(4x+2)

x = -1

f(-1) = 12 / [4(-1)+2]

f(-1) = 12 / (-4+2)

f(-1) = 12 / -2

f(-1) = -6
5 0
3 years ago
Let s(t) be the position function of a body moving along a coordinate line; s(t) is measured in feet and t in seconds, where t ≥
Murrr4er [49]
S (0) = (15*0)/(0 + 5) = 0/5 = 0
6 0
3 years ago
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