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Anastaziya [24]
2 years ago
10

WILL GIVE BRAINLIEST b. Describe the function over each part of its domain. State whether it is constant, increasing, or decreas

ing, and state the slope over each part.

Mathematics
1 answer:
True [87]2 years ago
5 0

Answer:

When x <= 8000

The cost remains constant at 0.35 when x increases from 0 to 8000

The slope of cost function over this part is 0

When 8000 < x <= 20000

The cost remains constant at 0.75 when x increases from 8000 to 20000

The slope of cost function over this part is 0

When 20000 < x <= 42000

The cost decreases when x increases from 20000 to 42000

The slope of cost function

m =  \frac{y2 - y1}{x2 - x1}  \\  =    \frac{(0.83 -  \frac{40000}{200000}) - (0.83 -  \frac{20000}{200000})}{40000 - 20000}

m= -5 × 10^-6

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Help please thanks!!!
Andreyy89
You already have the right Answer which is b
6 0
3 years ago
Read 2 more answers
Find the area of the path, 5 m wide, is surrounded outside the square pond of length 40 m​
frez [133]

Answer:

200 m.

Step-by-step explanation:

Step 1:

Length × Width = Area      Equation

Step 2:

5 × 40      Multiply

Answer:

Area = 200

Hope This Helps :)

8 0
3 years ago
A customer suspects that one brand of cereal does not fill
jarptica [38.1K]

Answer:

I think thr answer mughr ve B for what it sais

7 0
3 years ago
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Rearrange w=3(2a+b)-4 to make a the subject
garik1379 [7]

Answer:

w-6b+4/6

Step-by-step explanation:

To get the answer you have to first open the bracket which will give you w=6a+6b-4.You then take 6b-4 to the other side to meet w after this divide all by 6 to make a the subject of the formula.

4 0
2 years ago
By 3:00 pm, the temperature had increased by another 5%F. Was the temperature at 3:00 pm positive or negative?How do you know?Wh
victus00 [196]

Answer:

Part a) The temperature at noon was -3°F

Part b) The temperature at 3:00 pm was +2°F

Part c) The temperature at 11:00 pm was -6°F

Step-by-step explanation:

The complete question is

When Leo woke up he saw that the temperature was -8°F. By noon the temperature has increased 5°F. Part a) What was the temperature at noon?

Part b) By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00 pm positive or negative?

Part c) By 11:00 pm, the temperature had dropped 8°F. Was the

temperature at 11:00 PM positive or negative? Explain.​

Part a) we know that

You can use a number line to adds the numbers

-8+5=-3°F

therefore

The temperature at noon was -3°F

Part b) we know that

the temperature increased by another 5 degrees

You can use a number line to adds the numbers

-3+5=+2°F

therefore

The temperature at 3:00 pm was +2°F

Part c) we know that

the temperature had dropped 8°F

You can use a number line to adds the numbers

2-8=-6°F

therefore

The temperature at 11:00 pm was -6°F

4 0
3 years ago
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