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prohojiy [21]
3 years ago
12

Solve using elimination. -5x – 7y = -15 --4x – 7y = -19

Mathematics
1 answer:
Sav [38]3 years ago
7 0
-5x+15 = -4x+19
x + 15 = 19
x = 4
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What is 5/11 in decimal form? (round your answer to the nearest hundredth.)?
natita [175]
5/11 in decimal form is .45
4 0
3 years ago
Please help, this makes no sense to me
aev [14]

Answer:

7/11

Step-by-step explanation:

Let X equal the decimal number

Equation 1:

X=0.63¯¯¯¯¯

With 2 digits in the repeating decimal group,

create a second equation by multiplying

both sides by 102 = 100

Equation 2:

100X=63.63¯¯¯¯¯

Subtract equation (1) from equation (2)

100XX99X===63.63...0.63...63

We get

99X=63

Solve for X

X=6399

Find the Greatest Common Factor (GCF) of 63 and 99, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 9,

63÷999÷9=711

Therefore

X=711

In conclusion,

0.63¯¯¯¯¯=711

used

https://www.calculatorsoup.com/calculators/math/decimal-to-fraction-calculator.php

6 0
3 years ago
The population of a city is modeled by the equation P(t)=232012e0.23t where t is measure in years. If the city continues to grow
Gennadij [26K]

In around 6.35 years, the population will be 1 million.

<h3> how many years will it take for the population to reach one million?</h3>

The population is modeled by the exponential equation:

P(t) = 232,012*e^{0.23*t}

Then we just need to solve the equation for t:

P(t) = 232,012*e^{0.23*t} = 1,000,000

Let's solve that:

232,012*e^{0.23*t} = 1,000,000\\\\e^{0.23*t} = 1,000,000/232,012 = 4.31\\

If we apply the natural logarithm to both sides:

ln(e^{0.23*t}) = ln(4.31)\\\\0.23*t = ln(4.31)\\\\t = ln(4.31)/0.23 = 6.35

So in around 6.35 years, the population will be 1 million.

If you want to learn more about exponential equations:

brainly.com/question/11832081

#SPJ1

5 0
1 year ago
Find the inverse function of
shtirl [24]

Answer:

f(x) = 20x - 4 \\ substitute \: y \: for \: f(x) \\ y = 20x - 4 \\ interchange \: x \: and \: y \\ x = 20y - 4 \\ swap \: the \: sides \: of \: the \: equation \\ 20y - 4 = x \\ move \: the \: constant \: to \: the \: right \: hand \\ 20y = x + 4  \\ divide \: both \: sides \: by \: 20 \\ y =  \frac{1}{20} x +  \frac{1}{5}  \\ substitute \: f {}^{ - 1} (x) \: for \: y \\ f {}^{ - 1} (x) =  \frac{1}{20} x +  \frac{1}{5}

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

Thus, domain of f(x): x∈R = range of f¯¹(x)

and range of f(x): x∈R =domain of f¯¹(x)

3 0
2 years ago
Line 2x-4y-7=0 meets the x axis at point (k,0). Find the value of k
kolbaska11 [484]
K=4
add seven on both sides
2x-4y=7
add 4y on both sides
2x=7+4y
divide 2 on both sides
x=7+4y/2
plug that into original equation
2(7+4y/2)-4y-7=0
7 and 4y cancel out
2(2)=0
4=0
4 0
3 years ago
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