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Tasya [4]
2 years ago
10

I have to right a written expression of reflection what do i right

Physics
1 answer:
skad [1K]2 years ago
6 0
Hi there. I can help you, but I need to ask a few questions first.
You want to know what to write on a question that asks what the written expression of a reflection. Please tell me if that is what you are asking so I can help you.
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A thin, metallic spherical shell of radius 0.187 m has a total charge of 6.53×10−6 C placed on it. A point charge of 5.15×10−6 C
MAVERICK [17]

Answer: a) 112.88 * 10^3 N/C; b) The electric field point outward from the center of the sphere.

Explanation: In order to solve this problem we have to use the gaussian law so we use a gaussian surface at r=0.965 m and the electric flux is equal to Q inside/εo

E* 4*π*r^2= Q inside/εo

E= k*Q inside/r^2= 9*10^9*(6.53+5.15)μC/(0.965)^2=122.88 * 10 ^3 N/C

5 0
3 years ago
An object has 16N of force being applied to the right, 16N of force being applied to the left, and 4N of force being applied dow
goldenfox [79]

Answer:

4N downward

Explanation:

the 16N left and right cancel each other out, so you are left with the 4N downward.

6 0
2 years ago
Tell the order of vessels a blood cell travels through
il63 [147K]
It goes through your left atrium and right atrium
7 0
3 years ago
8. A crate of bananas weighing 3000 N is shipped from South America to New York, where it
LiRa [457]

Answer:

Mechanical advantage = 15

Explanation:

Given the following data;

Output force = 3000N

Input force = 200N

To find the mechanical advantage;

Mechanical advantage = output force/input force

Substituting into the equation, we have

Mechanical advantage = 3000/200

Mechanical advantage = 15

3 0
2 years ago
Anne releases a stone from a height of 2 meters. She measures the kinetic energy of the stone at 9.8 joules at the exact point i
insens350 [35]
A. 0.5kg

To get this answer you need to follow the equation of KE=0.5*mv^2 
But we don't have the m part in the equation. So just plug in the numbers to see which works best, though I can tell you before we do that the answer would be a. 

As you may know, gravity, is a force of 9.8 m/s. And we want to get 9.8 Joules. So if we take a half a kg stone, release it at one meter, we get half of the normal gravity pull, 4.90 Joules. That means if we take half a kg stone and drop it at a doubled height, we get 9.8 Joules.

That is also to say that if we have a 1kg stone and drop it at one meter you will get the normal pull of gravity in Joules, 9.8J. 

Be careful though, this does not mean if you drop a 1kg stone and a .5 kg stone the 1kg will hit first. This simply means that the 1kg stone will have twice the Joules that the .5kg stone has.
7 0
3 years ago
Read 2 more answers
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