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Jlenok [28]
3 years ago
14

Calculate the AMA of an access ramp if it takes 255 N of force to push a person in a wheelchair having a combined weight of 764

N up the incline.
a)2.50
b)2.95
c)3.00
d)1,020
Physics
1 answer:
Andreyy893 years ago
7 0
Actual Mechanical Advantage(AMA) = Weight / Force
Here, Weight = 764 N
Force = 255 N

Substitute the values in to the expression, 
AMA = 764 / 255
AMA = 2.99

After rounding-off to the nearest tenth value, it would be 3

Finally, option C would be your answer.

Hope this helps!
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Answer:

As you may know, each element has a "fixed" number of protons and electrons.

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3 years ago
Modify how could you charge the electric circuit shown below to allow lightbulb a to stay lit even if lightbulb b is removed fro
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A 0.90-kg falcon is diving at 28.0 m/s at a downward angle of 35° . It catches a 0.325-kg pigeon from behind in midair. What is
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Answer:

22.11 m / s

Explanation:

The falcon catches the prey from behind means both are flying in the same direction ( suppose towards the left )

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( falcon was flying in south east direction making 35 degree from the east )

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= 20.64 i - 14.45 j

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= 7 i

initial momentum = .325 x 7i

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If final velocity of composite mass of falcon and pigeon be V

Applying law of conservation of momentum

( .9 + .325) V = 20.64 i - 14.45 j +2.275 i

V = ( 22.915 i - 14.45 j ) / 1.225

= 18.70 i - 11.8 j

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= √ [  (18.7 )² + ( 11.8 )²]

= 22.11 m / s

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4 years ago
Note that the simulation allows you to also display the force of the smaller moon
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the force that the planet exerts on the moon is equal to the force that the moon exerts on the planet

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4 0
3 years ago
A mixture of helium and oxygen is used in scuba diving tanks to help prevent ""the bends"". 46 L helium and 12 L oxygen are comb
marin [14]

Answer

given,

For helium

Volume,V = 46 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₁ = ?

number of moles

we know

P V = n R T

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For oxygen

Volume,V = 12 L

Pressure,P = 1 atm

Temperature,T = 25°C  =  273 +25 = 298 K

R=0.0821 L . atm /mole.K

n₂ = ?

number of moles

we know

P V = n R T

n_2 =\dfrac{12 \times 1}{0.0821\times 298}

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P_1=\dfrac{n_1 R T}{V}

P_1=\dfrac{1.89\times 0.0821\times 298}{5}

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Partial pressure of oxygen

P_2=\dfrac{n_2 R T}{V}

P_2=\dfrac{0.49\times 0.0821\times 298}{5}

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total pressure

    P = P₁ + P₂

    P = 9.25 + 2.39

    P = 11.64 atm

8 0
3 years ago
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