Answer:
The magnitude of the electrostatic force is 120.85 N
Explanation:
We can use Coulomb's law to find the electrostatic force between the down quarks.
In scalar form, Coulomb's law states that for charges
and
separated by a distance d, the magnitude of the electrostatic force F between them is:

where
is Coulomb's constant.
Taking the values:


and knowing the value of the Coulomb's constant:

Taking all this in consideration:


True : <span>There are numerous third-class </span>levers<span> in the human </span>body<span>; one example can be illustrated in the elbow joint</span>
We have that the electric field at the center of the metal ball due only to the charges on the surface of the metal ball is

From the question we are told that
A solid metal ball of radius 1.5 cm
bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing
uniformly distributed charge of -7 nC
The distance between the centers of the balls is 9 cm
Generally the equation for the electric field is mathematically given as


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Answer:
W = 735.75[J]
Explanation:
Work is defined as the product of force by distance. Therefore we can use the following equation.

where:
W = work [J] (units of Joules)
F = force [N] (units of Newtons)
d = distance = 3 [m]
But first, we must determine the force that is equal to the product of mass by gravity (weight of the body).
![F=m*g\\F=25*9.81\\F=245.25[N]](https://tex.z-dn.net/?f=F%3Dm%2Ag%5C%5CF%3D25%2A9.81%5C%5CF%3D245.25%5BN%5D)
![W=F*d\\W=245.25*3\\W=735.75[J]](https://tex.z-dn.net/?f=W%3DF%2Ad%5C%5CW%3D245.25%2A3%5C%5CW%3D735.75%5BJ%5D)
That was sun as some smaller masses formed planets and other remaining formed sun