Answer:
See details below
Explanation:
The balanced reaction equation is given below:
+
→
+ ![10H_{2} O](https://tex.z-dn.net/?f=10H_%7B2%7D%20O)
Mole fraction of CO2 to H20
= 8/10 = ![\frac{4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D)
Mole ratio of C4H10 to CO2 is 2:8 = 1:4
1 mole of n-butane - 38.12 g
4 moles - ?
= 152.48g fuel consumed.
Answer:
Strontium (St)
Explanation:
The atom that will have a larger radius than zinc is strontium, Sr.
Atomic radius is defined as the half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.
- Across the period atomic radii decreases progressively due to the increase in nuclear charge.
- Down a group atomic radii increase progressively due to the successive shells of electrons being added.
- Since strontium satisfies the criteria, it has the larger atomic radius.
From what i can gather it looks like d
Answer:
56°
Explanation:
First calculate ![a:](https://tex.z-dn.net/?f=a%3A)
![a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}](https://tex.z-dn.net/?f=a%3D2%20R%20%5Csqrt%7B2%7D%3D2%280.1246%29%20%5Csqrt%7B2%7D%3D0.352%20%5Cmathrm%7Bnm%7D)
The interplanar spacing can be calculated from:
![d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}](https://tex.z-dn.net/?f=d_%7B111%7D%3D%5Cfrac%7Ba%7D%7B%5Csqrt%7B1%5E%7B2%7D%2B1%5E%7B2%7D%2B1%5E%7B2%7D%7D%7D%3D%5Cfrac%7B0.352%7D%7B%5Csqrt%7B3%7D%7D%3D0.203%20%5Cmathrm%7Bnm%7D)
The diffraction angle is determined from:
![\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D%5Cfrac%7Bn%20%5Clambda%7D%7B2%20d_%7B111%7D%7D%3D%5Cfrac%7B1%280.1927%29%7D%7B2%280.2035%29%7D%3D0.476)
Solve for ![\theta](https://tex.z-dn.net/?f=%5Ctheta)
![\theta=\sin ^{-1}(0.476)=28^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D%5Csin%20%5E%7B-1%7D%280.476%29%3D28%5E%7B%5Ccirc%7D)
The diffraction angle is:
![2 \theta=2\left(28^{\circ}\right)=56^{\circ}](https://tex.z-dn.net/?f=2%20%5Ctheta%3D2%5Cleft%2828%5E%7B%5Ccirc%7D%5Cright%29%3D56%5E%7B%5Ccirc%7D)