3 years ago

What is the charge of an electron A. -1 B. 0 C. +1 D. +2

Chemistry

1 answer:

Gelneren [198K]3 years ago

6 0

Answer:

Explanation:

I believe it is negative 1.

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1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage

Jet001 [13]

Answer:

$V_{p} = 15 V$

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

$\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}$

Making Vp the subject of formula;

$V_{p} = \frac{N_{p}}{N_{s}} * V_{s}$

Substituting into the equation, we have;

$V_{p} = \frac{1}{8} * 120$

$V_{p} = \frac{120}{8}$

$V_{p} = 15 V$

Therefore, the voltage in the primary coil, Vp is 15 Volts.

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