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Stels [109]
3 years ago
12

What is the charge of an electron A. -1 B. 0 C. +1 D. +2

Chemistry
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

A

Explanation:

I believe it is negative 1.

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The system co2(g) + h2(g) ⇀↽ h2o(g) + co(g) is at equilibrium at some temperature. at equilibrium a 4.00 l vessel contains 1.00
Marina CMI [18]

<u>Answer:</u> The moles of CO_2 added to the system is 7.13 moles

<u>Explanation:</u>

We are given:

Moles of CO_2 at equilibrium = 1.00 moles

Moles of H_2 at equilibrium = 1.00 moles

Moles of H_2O at equilibrium = 2.40 moles

Moles of CO at equilibrium = 2.40 moles

Volume of the container = 4.00 L

Concentration is written as:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}

The given chemical equation follows:

CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)

The expression of K_c for above equation follows:

K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}

Putting values in above equation, we get:

K_c=\frac{(\frac{2.40}{4.00})\times (\frac{2.40}{4.00})}{(\frac{1.00}{4.00})\times (\frac{1.00}{4.00})}\\\\K_c=5.76

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of CO = 0.791 mol/L

Volume of solution = 4.00 L

Putting values in above equation, we get:

0.791M=\frac{\text{Moles of CO}}{4.00L}\\\\\text{Moles of CO}=(0.791mol/\times 4.00L)=3.164mol

Extra moles of CO = (3.164 - 2.40) = 0.764 moles

Let the moles of CO_2 needed be 'x' moles.

Now, equilibrium gets re-established:

              CO_2(g)+H_2(g)\rightleftharpoons H_2O(g)+CO(g)

Initial:       1.00      1.00              2.40       2.40

At eqllm:   (0.236+x)   0.236      3.164     3.164

Again, putting the values in the expression of K_c, we get:

5.76=\frac{(\frac{3.164}{4.00})\times (\frac{3.164}{4.00})}{(\frac{0.236+x}{4.00})\times (\frac{0.236}{4.00})}\\\\5.76=\frac{10.011}{0.056+0.236x}\\\\x=7.13

Hence, the moles of CO_2 added to the system is 7.13 moles

4 0
3 years ago
A) what is the light source for a plant growing in the shade?
Sholpan [36]

a.) Plants that thrive in the shade are often able to hold on to sunlight for extensive periods of time; they're in a sense like the camels of the plaNt WoRld.

b.) Though artificial lights are not nearly as beneficial as the sun, one could invest in one of them plant growing light thingies, but sun-loving plants might be sad if u do this instead of letting them soak in ePic rays from the sun.

4 0
3 years ago
What kind of change is sodium hydroxide dissolving in water
Korolek [52]
Physical change because water is not a gas or change . you can see through it. 
6 0
4 years ago
A sample of argon (Ar) gas has a volume of 7.31 L at a pressure of
Pie

Answer:

17.1 L

Explanation:

P1V1/T1  =  P2V2/T2        T is in K

P1V1/T1 * T2/P2 = V2

735 * 7.31 / (45+273.15)  * (55+ 273.15)/325 = V2

V2 = 17.1 L

3 0
2 years ago
Which combination of reagents used in the indicated order with benzene will give m-nitropropylbenzene? a. 1) CH3CH2CH2Cl/AlCl3,
VladimirAG [237]

Answer:

1) HNO3/H2SO4, 2) CH3CH2CH2Cl/AlCl3

Explanation:

Benzene is a stable aromatic compound hence it undergoes substitution rather than addition reaction.

When benzene undergoes substitution reaction, the substituent introduced into the ring determines the position of the incoming electrophile.

If I want to synthesize m-nitropropylbenzene, I will first carry out the nitration of benzene using HNO3/H2SO4 since the -nitro group is a meta director. This is now followed by Friedel Craft's alkykation using CH3CH2CH2Cl/AlCl3.

6 0
3 years ago
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