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denis23 [38]
2 years ago
11

What is the solution to the equation 6x-3=-51

Mathematics
2 answers:
docker41 [41]2 years ago
6 0
6x - 3 = -51
add 3 to both sides
6x = -48
divide by 6 to both sides
× = -8
Shkiper50 [21]2 years ago
3 0

Answer:

B for plato users

Step-by-step explanation:

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The figure is made up of a square and a rectangle. Find the area of the shaded region.
sergij07 [2.7K]

Answer:

9

Step-by-step explanation:

second box is nine because it is half of the 3 x 6 part

6 0
2 years ago
(W+4)(3w-2) please solveeed
Shkiper50 [21]

Step-by-step explanation:

{:}\longrightarrow\sf (w+4)(3w-2)

{:}\longrightarrow\sf w(3w-2)+4 (3w-2)

{:}\longrightarrow\sf 3w^2-2w+12w-8

{:}\longrightarrow\sf 3w^2+10w-8

7 0
3 years ago
Read 2 more answers
Human blood has an approximate pH of 7.3. Which substance is more basic than human blood?
ratelena [41]


so, 7 is neutral anything past 7 is considered basic.

answer: <em>a water and ammonia solution with a pH of 11 (very basic).</em>

<em />any number under 7 is acidic and of course there are different degrees of acidic just like there are different degrees of basicity.   

______________________________________________________________

- stomach's digestive juices, would be considered very acidic

-apple juice is also acidic but not as acidic  like stomach juices.

- grape juice, is becoming less acidic.

________________________________________________________________

Hopefully this helped and good luck.

5 0
3 years ago
What are the values of x and y in PQRS? What are PR and SQ?
mamaluj [8]

Step-by-step explanation:

sol;

x+1=y...(1)

3y-7=2x....(2)

or, 3(x+1)-72x [from (1)]

or, 3x+3-7=2x

or, 3x-2x=7-3

     x=4

now,

putting the value of x in (1)

y=x+1

 =4+1

 =5

PR and SQ are the diagonal of PQRS.

4 0
2 years ago
Let T: Mmxn(R)Mmxn(R) be the function defined
alexandr402 [8]

Answer:

True. See the explanation and proof below.

Step-by-step explanation:

For this case we need to remeber the definition of linear transformation.

Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:

1) T(x+y) = T(x) + T(y)

2) T(cv) = cT(v)

For all vectors x,y \in V and for all scalars c \in R. And A is called the domain and B the codomain of T.

Proof

For this case the tranformation proposed is t: M_{mxn} (R) > M_{nxm} (R)

Where T(A) = A^T

For this case we have the following assumption:

1) The transpose of an nxm matrix is an nxm matrix

And the following conditions:

2) T(A+B) = (A+B)^T = A^T + B^T = T(A) + T(B)

And we can express like this T(A+B) =T(A) + T(B)

3) If A \in M_{mxn}(R) and c \in R then we have this:

T(cA) = (cA)^T = cA^T = cT(A)

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.

5 0
3 years ago
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