Answer:
that puts the solution in the form ...
variable is ...
Step-by-step explanation:
It isn't always.
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Often, we like to have a solution be in the form ...
variable is ...
So, for an inequality, that puts the variable on the left:
x > 3
y < 27
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Personally, I like to see the answer in a form that has the variable and its values in the same relation as on a number line. This means, my preferred inequality symbols are < or ≤, since those have the smaller numbers on the left. I would write the first example above as ...
3 < x
showing that the shaded portion of the number line (representing possible values of the variable) is to the right of the open circle at 3. For me, it is more mental effort to translate x > 3 to the same image.
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The forms we choose to use are all about making communication as easy as possible.
<h3>
Answer:</h3>
C) y = 6x
<h3>
Step-by-step explanation:</h3>
Pick any point. It is often convenient to use x = 1 (no marked point) or x = 10 (where y = 60).
Use these values to see which equation agrees.
A: 60 ≠ (1/6)·10
B: 60 ≠ 2·20
C: 60 = 6·10
D: 60 ≠ 12·10
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Or, you can solve ...
... y = kx
for k, using the point values you found on the graph.
... 60 = k·10
... 60/10 = k = 6 . . . . . divide by 10
This makes the equation be ...
... y = 6x . . . . . . matches selection C
You cant simplify it . it is already simplified
Given:
• Total number of cans collected = 150
,
• Percent of cans that were soda = 58%
Let's find the number of other cans he collected.
To find the number of other cans, since the percent of soda is 58%, let's find the pecent of other cans.
Percent of other cans = 100% - 58% = 42%
The percent of other cans collected was 42%.
Now, to find the number of other cans collected, let's find 42% of the total number of cans collected 150.
We have:
Therefore, the number of other cans collected is 63 cans.
ANSWER:
63 cans
Ok sure! Let's start with the marbles first. We have one red one blue and one green. There is a red and a blue cube. All we do is list the possible combinations of one marble and one cube. The answer would be : 1 blue marble, 1 blue cube. 1 red marble, 1 blue cube. 1 green marble, 1 blue cube. Then again but with the red cube. So in all, there are 6 possible combinations. Hope this helps. ☺️
