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xxTIMURxx [149]
3 years ago
7

Suppose you have to use right-triangle trigonometry to find the apothem of a regular polygon. Which is greater, the apothem or t

he radius of the polygon?
Mathematics
1 answer:
asambeis [7]3 years ago
8 0
The apothem represents one side of the right triangle to be solved. Specifically, it represents the height of the triangle.
 The radius of the polygon represents the hypotenuse of the right triangle that is going to be solved.
 Therefore, we can infer that the radius of the polygon is greater than the apothem because the hypotenuse is greater than all sides of a triangle.
 Answer:
 the radius of the polygon is greater
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1/2(x+10)= 1/4 (x-8) x= <br> (must be a fraction)
Alex_Xolod [135]

Answer:

x=-9\frac{1}{3}

Step-by-step explanation:

\frac{1}{2}(x+10)=\frac{1}{4}(x-8)

\frac{1}{2}x+5=\frac{1}{4}x-2

\frac{1}{2}x-\frac{1}{4}x=-5-2

\frac{3}{4}x=-7

x=-\frac{28}{3}=-9\frac{1}{3}

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3 years ago
HELP ME MATH ILL GIVE YOU BRAINLIEST
s344n2d4d5 [400]

Answer:

  • zeros: x = -3, -1, +2.
  • end behavior: as x approaches -∞, f(x) approaches -∞.

Step-by-step explanation:

I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.

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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...

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which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.

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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).

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3 years ago
A farm lets you pick 3 pints of raspberries for 12.00 what is the price per pint/
BaLLatris [955]

Answer:

$4

Step-by-step explanation:

I tried to make it as simple as possible.

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2 years ago
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SVETLANKA909090 [29]
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3 years ago
Below are three different hypothesis tests about population proportions. For each test, use StatKey and the information given to
Ilia_Sergeevich [38]

Answer:

1a) p-hat=0.38

1b) P=0.08

1c) The null hypothesis is not rejected

2a) p-hat=0.64

2b) P=0.0027

2c) The null hypothesis is rejected

3a) p-hat=0.55

3b) P=0.153

3c) The null hypothesis is not rejected

Step-by-step explanation:

(1) H0: p = 0.3 vs Ha: p ≠ 0.3. In their survey, they had a count of 38 using a sample size n=100.

1a) The p-hat is p-hat=38/100=0.38.

1b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.3*0.7}{100}}=0.046

The sample size is n=100.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.38-0.3}{0.046}=\frac{0.08}{0.046}= 1.74

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.74 is P=0.08.

1c) The null hypothesis is not rejected.

(2) H0: p = 0.7 vs Ha: p ≠ 0.7. In their survey, they had a count of 320 using a sample size n=500.

2a) The p-hat is p-hat=320/500=0.64.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.7*0.3}{500}}=0.02

The sample size is n=500.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.64-0.7}{0.02}=\frac{-0.06}{0.02}=-3

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=3 is P=0.0027.

2c) The null hypothesis is rejected.

(3) H0: p = 0.6 vs Ha: p < 0.6. In their survey, they had a count of 110 using a sample size n=200.

2a) The p-hat is p-hat=110/200=0.55.

2b) The standard deviation is

\sigma=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.6*0.4}{200}}=0.035

The sample size is n=200.

The z-value is:

z=\frac{\hat{p}-p}{\sigma}=\frac{0.55-0.6}{0.035}=\frac{-0.05}{0.035}=-1.43

As it is a two-sided test, the p-value considers both tails of the distribution.

The p-value for this |z|=1.43 is P=0.153.

2c) The null hypothesis is not rejected.

8 0
3 years ago
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