Answer:
<h3>25m</h3>
Step-by-step explanation:
Perimeter of the rectangular pasture P = 2(L+W)
Area A = LW
L is the length
W is the width
Given
Perimeter = 110m
Area = 750m
If the length of the pasture is 40m longer than the width, then L = W+40
110 = 2L+2w
55 = L+W .....1
750 = LW.....2
Solving simultaneously
from 1; L = 55-W
substitute into 2;
750 = (55-W)W
750 = 55W-W²
-W²+55W -750 = 0
W²-55W+750 = 0
(W²-25W)-(30W+750) = 0
W(W-25)-30(W-25) = 0
(W-25)(W-30) = 0
W-25 = 0 and W-30 = 0
w = 25m and 30m
Since L = 55-W
L = 55-25 = 30m and;
L = 55-30 = 25m
Since we are told that length id longer than the width then, the width we are going to use is 25m
Answer:64Step-by-step explanation:
Answer:
Step-by-step explanation:
2x + 10 = 28
Bringing like terms on one side
2x = 28 - 10
2x = 18
x = 18/2 = 9
You could factor a 7 out of 7 + 14 to get 7(1 + 2).
This would equal the same thing as 7 + 14, which is 21.
7 * 3 = 21.
21 can be factored like so:
1 * 21 = 21
3 * 7 = 21
Answer:
d=3
Step-by-step explanation:
by using distance formula
d=√(x2-x1)²+(y2-y1)²
let the points be A(-3,2) B(0,2)
d=√(0--3)²+(2-2)²
d=√(+3)²+(0)²
d=√9
d=3