Answer: Brielle will run the marathon faster.
Brielle = 104.8 minutes
Joshua = 157.2 minutes
Step-by-step explanation:
Speed rate = distance /time
Brielle = 1.25 /10 = 0.125 miles per minute
Joshua = 1.5/18 = 0.083333 =1/12 miles per minute
Since 0.125 (Brielle) > 1/12 (Joshua)
Brielle will run the marathon faster.
To calculate the time that takes each one to run the entire race (13.1 miles)
Time= distance / speed
- Brielle = 13.1 /0.125 = 104.8 minutes
- Joshua = 13.1 / (1/12)= 157.2 minutes
Feel free to ask for more if needed or if you did not understand something.
Answer:
(−0.103371 ; 0.063371) ;
No ;
( -0.0463642, 0.0063642)
Step-by-step explanation:
Shift 1:
Sample size, n1 = 30
Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm
Shift 2:
Sample size, n2 = 25
Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17
Mean difference ; μ1 - μ2
Zcritical at 95% confidence interval = 1.96
Using the relation :
(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)
(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)
Lower boundary :
-0.02 - 0.0833710 = −0.103371
Upper boundary :
-0.02 + 0.0833710 = 0.063371
(−0.103371 ; 0.063371)
B.)
We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.
C.)
For sample size :
n1 = 300 ; n2 = 250
(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)
Lower boundary :
-0.02 - 0.0263642 = −0.0463642
Upper boundary :
-0.02 + 0.0263642 = 0.0063642
( -0.0463642, 0.0063642)
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<em>Hi there!</em>
<em>~</em>
<em>1:10000 would be the scale.</em>
<em>❀Hope this helped you!❀</em>
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