Hello!
We have the following data:
KE (Kinetic Energy) = ? (in Joule)
m (mass) = 0.5 Kg
v (speed) = 10 m/s
<span>Formula to calculate kinetic energy:
</span>
<span>
Solving:
</span>
I hope this helps! =)
The answer to this is the plate tectonics theory.
The earth's lithosphere is divided into large, moving sections which are called the tectonics plates.
Hope this helped :)
Have a great day
<span>It's another energy balance equation, though: energy to start with is the same as energy that you end with. Suppose that we start a distance r0 from the Earth and end a distance r1 from the Moon, then the energy balance gives:
1 v02 - G M / r0 - G m / (D - r0) = 1 v12 - G M / (D - r1) - G m / r1
...where m is the moon's mass.
One simple limit takes D ? ? and 1 v02 ? G M / r0 (the escape velocity equation), to yield:
1 v12 ? G M / r1
v1 ? ?( 2 G M / r1 ) = 2377 m/s.</span>
Answer:
W = 270.9 J
Explanation:
given,
F(x) = (12.9 N/m²) x²
work = Force x displacement
dW = F .dx
the push-rod moves from x₁= 1 m to x₂ = 4 m
integrating the above
![W = 12.9\times [\dfrac{x^3}{3}]_1^4 dx](https://tex.z-dn.net/?f=W%20%3D%2012.9%5Ctimes%20%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%5D_1%5E4%20dx)
`![W = 12.9\times [\dfrac{4^3}{3}-\dfrac{1^3}{3}] dx](https://tex.z-dn.net/?f=W%20%3D%2012.9%5Ctimes%20%5B%5Cdfrac%7B4%5E3%7D%7B3%7D-%5Cdfrac%7B1%5E3%7D%7B3%7D%5D%20dx)
W = 270.9 J
work done by the motor is W = 270.9 J
