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MAXImum [283]
3 years ago
10

What is the common size for air mass?

Physics
1 answer:
Serggg [28]3 years ago
5 0
Thecorrect answer is B. 

hope this helps brainliest would be cool if not its fine

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Ben and Dan both weigh 600 N. They are doing pull-ups together. Each pull-up is 0.5 meters of distance. How much work do they ea
Natasha2012 [34]

Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

5 0
2 years ago
I need help with #4 and #5?
algol [13]

A

Explanation:

just  pick a

3 0
2 years ago
A cart rolling down an incline for 2.0 seconds has a beginning speed of 3.0m/s, what Is the final speed or volocity?​
Kryger [21]

Answer:

1.5 seconds

Explanation:

V=S/T

V=3/2

V=1.5 seconds

8 0
3 years ago
Real bodies emit and absorb more radiation than a blackbody at the same temperature. True or False
monitta

Answer: False

Explanation:

Relative to the concept of radiations, a black body is an object capable of absorbing any form of electromagnetic radiation irrespective of its frequency or angle of incidence when incident on such object.

However, the same cannot be said about real bodies as real bodies are those which reflect all rays incident on them completely and uniformly in all directions.

One very important characteristic of black bodies is that they are ideal emmiters.

The concept of emmisivity is brought about by the existence of real bodies .

This is due to the fact that they are only able to emit radiation at a fraction of the black body energy levels.

Please note that by convention, the emmisivity of a real body is always less thaan 1.

As such they are not able to emit as much radiation as a black body at the same temperature.

3 0
3 years ago
Um corpo de massa 50g recebe 300 calorias e sua temperatura sobe de -10°C até 20°C. Determine a capacidade térmica do corpo e o
kykrilka [37]

The specific heat capacity of the substance is 0.963 J/g^{\circ}C

Explanation:

When an object of mass m is supplied with a certain amount of energy Q, its temperature increases according to the equation:

Q=mC_s \Delta T

where

m is the mass of the object

C_s is its specific heat capacity

\Delta T is the increase in temperature of the object

In this problem, we have

Q=300 cal \cdot 4.814 = 1444.2 J

m = 50 g

\Delta T = 20C-(-10C)=30^{\circ}C

Therefore, we can solve for C_s to find its specific heat capacity:

C_s = \frac{Q}{m\Delta T}=\frac{1444.2}{(50)(30)}=0.963 J/gC

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

7 0
3 years ago
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