If we decrease the amount of force and keep all other factors the same what will happen to the amount of work

alekssr [168]

Answer:

energy : the ability to cause change

work : is force x distance or when an object moves a distance due to a specific force (measured in units of newtons-meters)

potential energy : is stored energy

kinetic energy : is energy in motion

mechanicle energy : the energy of motion such as a moving vechile

thermal energy : total kinetic energy in moving partsticles, like in boiling water (energy of heat)

chemical : energy stored in chemical bonds, like in plants

electromagnetic : waves with electric and magnetic properties , such as light

nuclear energy : energy stored in the nuclear atoms

all dish was from mah brain u better mark meh brainliest >:}

~batmans wife dun dun dun...aka ~serenitybella

5 0

4 years ago

A capacitor in an LC oscillator experiences a maximum potential difference of 88V and a maximum energy of 2002 uJ. At a certain

VLD [36.1K]

Answer:

Explanation:

maximum energy of capacitor

E = 1/2 C V ²

C is capacitance of capacitor and V is potential difference

given V = 88 V

E = 2002 x 10⁻⁶ J

Putting the values

2002 x 10⁻⁶ = 1/2 x C x 88²

C = .517 x 10⁻⁶ F .

In the second case

Energy E = 125 x 10⁻⁶ J .

C = .517 x 10⁻⁶

V = ?

E = 1/2 C V ²

125 x 10⁻⁶ = 1/2 x .517 x 10⁻⁶ x V²

V² = 483.55

V = 21.98 V .

6 0

4 years ago

A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediat

N76 [4]

Answer:

p_k=\sqrt{p_x^2+p_y^2}}

Explanation:

Apply the momentum in each direction knowing that the impact is at the same time for the pieces so

$p_x=m_1*v_1$

$p_x=200g*2.0m/s=0.4kgm/s$

$p_y=m_2*v_2$

$p_y=235g*1.5m/s=0.3525kgm/s$

So the momentum in the other piece can be find knowing that

$p_x^2+p_y^2=p_k^2$

So:

$p_k=\sqrt{p_x^2+p_y^2}}$

$p_k=\sqrt{0.4^2+0.3525^2}}=\sqrt{0.2842 kg^2*m^2/s^2}$

$p_k=0.5331kg*m/s$

To find the velocity knowing the mass

$p_k=m_k*v_k$

$v_k=\frac{p_k}{m_k}=\frac{0.5331 kg*m/s}{0.10kg}$

$v_k=5.331 m/s$

4 0

3 years ago

1. Explain a stretching routine for your work environment. As you consider your routine, keep in mind the specific individuals w

weeeeeb [17]

Answer:

Explanation:

A stretching routine should target most of the main muscles in the body and at least one stretching exercise per section of the body. Also in a work environment since individual's sizes, ages, and cultures vary you should design a routine that is for beginners and very easy and effective. Regardless, each individual should be able to move at their own pace and push as far as they are physically able. One such routine would be the one in the attached picture below which targets all major areas, is easy and effective. It starts at the neck muscles and works its way down the arms, back, and legs.

3 0

3 years ago

Which is not an example of how an object gains elastic potential energy by stretching?

lora16 [44]

C because you don’t put a force of which you choose and the force wouldn’t be strong enough

4 0

4 years ago