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rjkz [21]
3 years ago
14

How does gravity keep the moon in orbit around earth

Physics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Explanation:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Answer is above

<em><u>Hope this helps.</u></em>

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[04.05] An atom has an atomic number of 12 and a mass number of 25. How many neutrons does the atom have?​
gizmo_the_mogwai [7]

Answer: is  13

Explanation:

6 0
3 years ago
"The drawing shows three layers of different materials, with air above and below the layers. The interfaces between the layers a
My name is Ann [436]

Answer:

Angle of incidence that entered material b= 63.1°

Angle of incidence between a and b = 55.9°

Explanation: Using the formular:

n1sintheta1= n2sintheta2

The light ray which enters material B will be

1.4Sin72.8° = 1.5Sin theta

1.3373= 1.5Sintheta

sintheta = 1.3373/1.5

Sin^-1 0.8916 = Theta

63.1 = theta

When the ray hits interface with material a

1.5Sin63.1 = 1.3 Sin theta

1.3374 = 1.3Sin theta

Sintheta= 1.3374/1.3

Sin theta = 1.0877

There will be total reflection off the boundary b c because sin theta exceeded 1 in value.

The equation should be

1.4sin63.1 = 1.4 sin theta

Sin theta=72.8°

When the ray hits air-c boundary:

1.4sin72.8=1.00sin theta

Sin theta=1.3374/1 =1.3374

There is total reflection.

In material a,the ray will:

1.3sin72.8° = 1.00sin theta

There will be total reflection when the ray hits a-b boundary.

1.3sin72.8= 1.5sintheta

Sin theta= 1.2419/ 1.5

Sin theta =0.8279

Theta= Sin^-10.8279= 55.88°

When ray hits c-air boundary

1.4sin63.1= 1.00sintheta

1.2485= sin theta = Toal reflection.

Therefore when the ray of light pass through the layers of material a, b and c the boundary with air on top and bottom will be total reflection.

7 0
3 years ago
A small fish is dropped by a pelican that is rising steadily at 0.50 m/s.
natima [27]

Answer:

(a)  24.025 m/s. downward.

(b)  31 m

Explanation:

From Newton's equation of motion,

(a)

v = u + gt ................... Equation 1

Where v = final velocity, u = initial velocity, g = acceleration due to gravity, t = time.

Note: Let upward velocity be negative and downward be positive

Given: u = -0.5 m/s (upward), t = 2.5 s

Constant : g = 9.81 m/s²

Substitute into equation 1

v = 0.5+9.81(2.5)

v = -0.5+24.525

v = 24.025 m/s. downward.

(b) using

s₁ = ut + 1/2gt²......................... Equation 2

Where s₁ = distance at which the fish fall after being dropped by the pelican

Given: u = - 0.5 m/s, t = 2.5 s, g = 9.81 m/s²

Substitute into equation 2

s₁ = -0.5(2.5) + 1/2(9.81)(2.5)²

s₁ = -1.25+30.656

s₁ = 29.41 m

also,

s₂ = vt ................ Equation 3

Where s₂ = the distance by which the pelican rise during this time.

Given: v = 0.5 m/s, t= 2.5 s

s₂ = 0.5(2.5)

s₂ = 1.25 m.

Note: Distance between the pelican and fish = s₁ + s₂

Distance between the pelican and fish  = 29.41+1.25

Distance between the pelican and fish  = 30.66

Distance between the pelican and fish ≈ 31 m

3 0
3 years ago
Part A Determine the magnitude of the x component of F using scalar notation. Fx F x = nothing lb Request Answer Part B Determin
maksim [4K]

As we know that force F makes an angle of 60 degree with X axis

so the X component is given as

cos60 = \frac{F_x}{F}

now we have

F_x = F cos60

F_x = 0.50 F

Similarly we know that force F makes an angle of 45 degree with Y axis

so the X component is given as

cos45 = \frac{F_y}{F}

now we have

F_y = F cos45

F_y = 0.707 F

Now for the component along z axis we know that

F_x^2 + F_y^2 + F_z^2 = F^2

now plug in all components

(0.707 F)^2 + (0.50 F)^2 + F_z^2 = F^2

0.5 F^2 + 0.25 F^2 + F_z^2 = F^2

F_z^2 = F^2(1 - 0.75)

F_z^2 = 0.25 F^2

F_z = 0.5 F

5 0
3 years ago
I need help
musickatia [10]

Answer:

C

Explanation:

4 0
3 years ago
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