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3 years ago

How does gravity keep the moon in orbit around earth

Physics

1 answer:

lidiya [134]3 years ago

3 0

Answer:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Explanation:

The moon's orbit draws the oceans to it, which triggers ocean tides. Force produces stars and planets by gathering the mass from which it exists.

Answer is above

<em><u>Hope this helps.</u></em>

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Find the heat given off if 1 kg of 125 degree C steam is cooled to 50 degree C water.

Gnom [1K]

T_i=125°C=398K
T_f=50°C=323K
c=4184J/kg°K
m=1kg
∆T=T_f-T_i=398-323=75K

$\\ \sf{:}\Rrightarrow Q=mc\Delta T$

$\\ \sf{:}\Rrightarrow Q=1(4184)(75)$

$\\ \sf{:}\Rrightarrow Q=313800J$

$\\ \sf{:}\Rrightarrow Q=313.8KJ$

4 0

3 years ago

Suppose the equation of the velocity of a car at any given time is Vx= 30m/s+(2.5m/s^3)t^2 Find the change in the velocity of th

mario62 [17]

Answer:

time=4, answer choice A

time=5.5, answer choice B

Explanation:

This is taken from the kinematic equation, v=vo+(1/2)at^2

Velocity at time 4 = 30+(2.5)(4)^2

Velocity at time 5.5 = 30+(2.5)(5.5)^2

Velocity at time 4 seconds = 70 m/s

Velocity at time 5.5 seconds = 105.63 m/s

3 0

3 years ago

A box of mass m = 23.0 kg is sliding along a horizontal frictionless surface at a speed vi = 7.10 m/s when it encounters a ramp

SashulF [63]

Answer:

d = 57.7 m

Explanation:

For this exercise we will use energy work theorems

W = ΔEm

Let's calculate the work of the rubbing force on the ramp

W = -fr d

The negative sign is because the force of friction opposes the movement

Newton's second law in the axis perpendicular to the ramp gives

N- W cos 21.8 = 0

N = mg cos 21.8

The equation for the force of friction is

fr = μN

fr = μ mg cos 21.8

Let's replace

W = - μ mg d cos 21.8

Let's look for energy in two points

Initial just before entering the ramp

Emo = K = ½ m v²

End the highest point where the body stops

$Em_{f}$ = U = mg y

We use trigonometry to find the height (y)

sin 21.8 = y / d

y = d sin 21.8

$Em_{f}$ = m g d sin 21.8

Let's replace

W = ΔEm = $Em_{f}$ - Em₀

- μ mg d cos 21.8 = mgd sin21.8 - ½ m v²

m g d (sin21.8 + μ cos 21.8) = ½ m v²

d = v² / (2 (sin21.8 + μ cos21.8))

d = 7.10² / (2 (sin21.8 + 0.0704 cos 21.8))

d = 50.41 /0.87345

d = 57.7 m

5 0

4 years ago

Kepler's first law states that planets orbit the Sun in a path called a(n)

larisa86 [58]

the correct answer is C.

7 0

3 years ago

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19 points!! plsss helpppp

Andrej [43]

Answer:

pretty sure its a

Explanation:

6 0

4 years ago

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