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schepotkina [342]
2 years ago
5

if the electron affinity for an element is a negative number, does it mean that the anion of the element is more stable than the

neutral atom?
Physics
1 answer:
USPshnik [31]2 years ago
8 0

Taking into account the definition of electron affinity, negative electron affinity means that the anion of the element is more stable than the neutral atom.

Electron affinity is the energy exchanged when a neutral, gaseous atom, and in its ground state, captures an electron to form the anion.

In other words, electronon Affinity is the energy that is given off when a neutral atom in the gaseous state captures an electron to become a negative ion.

The value can be positive or negative. A negative electron affinity means energy must enter in order to bind an electron to the ion, being an endothermic process. If electron affinity is positive, the process is exothermic and occurs spontaneously.

Then, the negative electron affinity (energy is released) occurs when the atoms acquire a more stable configuration when capturing an electron, so the attractive force will predominate. Positive electron affinity (energy is absorbed): occurs when you have to provide energy to the atom to capture the ion.

In summary, negative electron affinity means that the anion of the element is more stable than the neutral atom.

Learn more:

  • brainly.com/question/20715490?referrer=searchResults
  • brainly.com/question/11248964?referrer=searchResults
  • brainly.com/question/7022188?referrer=searchResults

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"The drawing shows three layers of different materials, with air above and below the layers. The interfaces between the layers a
My name is Ann [436]

Answer:

Angle of incidence that entered material b= 63.1°

Angle of incidence between a and b = 55.9°

Explanation: Using the formular:

n1sintheta1= n2sintheta2

The light ray which enters material B will be

1.4Sin72.8° = 1.5Sin theta

1.3373= 1.5Sintheta

sintheta = 1.3373/1.5

Sin^-1 0.8916 = Theta

63.1 = theta

When the ray hits interface with material a

1.5Sin63.1 = 1.3 Sin theta

1.3374 = 1.3Sin theta

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Sin theta = 1.0877

There will be total reflection off the boundary b c because sin theta exceeded 1 in value.

The equation should be

1.4sin63.1 = 1.4 sin theta

Sin theta=72.8°

When the ray hits air-c boundary:

1.4sin72.8=1.00sin theta

Sin theta=1.3374/1 =1.3374

There is total reflection.

In material a,the ray will:

1.3sin72.8° = 1.00sin theta

There will be total reflection when the ray hits a-b boundary.

1.3sin72.8= 1.5sintheta

Sin theta= 1.2419/ 1.5

Sin theta =0.8279

Theta= Sin^-10.8279= 55.88°

When ray hits c-air boundary

1.4sin63.1= 1.00sintheta

1.2485= sin theta = Toal reflection.

Therefore when the ray of light pass through the layers of material a, b and c the boundary with air on top and bottom will be total reflection.

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3 years ago
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Complete Question:

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Answer:

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Explanation:

If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

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