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Alekssandra [29.7K]
3 years ago
10

What happens to the average kinetic energy of a gas when the particles of the gas collide against each other at a constant tempe

rature and volume? The average kinetic energy remains constant. The average kinetic energy drastically increases. The average kinetic energy drastically decreases. The average kinetic energy gets added to the potential energy.
Chemistry
2 answers:
Triss [41]3 years ago
8 0

Answer:

the average kinetic energy remains constant

Explanation:

Collisions between gas particles are elastic. An elastic collision means there is no net gain or loss of kinetic energy due to the collision. This means a sample of gas will have a constant average kinetic energy at a constant temperature and volume.

LuckyWell [14K]3 years ago
5 0

Answer:

The average kinetic energy drastically increases.

Explanation:

The average kinetic energy drastically increases when the gas particles collide against each other at a constant temperature and volume because the collision will increase the heat content of gas at a particular temperature and gas particles begin to move faster as gain more kinetic energy.

Hence, the correct answer is "B".

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What is the percent composition of dinotrogen pentoxide? With work shown please
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Answer:

%N = 25.94%

%O = 74.06%

Explanation:

Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅

We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%

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What type(s) of intermolecular forces are expected between ch3ch2ch2ch2ch2oh molecules?
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Answer : Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

Explanation :

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Three types of inter-molecular forces are present in this molecule which are Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

  • Hydrogen-bonding : when the partial positive end of hydrogen is bonded with the partial negative end of another molecule like, oxygen, nitrogen, etc.
  • Dipole-dipole attraction : When the partial positively charged part of the molecule is interact with the partial negatively charged part of the molecule. For example : In case of HCl.
  • London-dispersion force : This force is present in all type of molecule whether it is a polar or non-polar, ionic or covalent. For example : In case of Br-Br , F-F, etc

Hydrogen-bonding is present between the oxygen and hydrogen molecule.

Dipole-dipole forces is present between the carbon and oxygen molecule.

London-dispersion forces is present between the carbon and carbon molecule.

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