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3 years ago

Large-scale environmental catastrophes _______.

Chemistry

1 answer:

Ymorist [56]3 years ago

3 0

Answer:

D. All of the Above

Explanation:

i just took the test on edgenuity

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How to balance lead and silver acetate yields lead (||) acetate and silver

arsen [322]

The given elements put into an equation using their symbols are as follows:
Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2

3 0

3 years ago

Which can cause auroras and disrupt satellite tranmission

schepotkina [342]

Ultraviolent radiation i believe

7 0

3 years ago

How many moles of oxygen gas are need to produce 5.53 x 10 moles of water (1)

SIZIF [17.4K]

Answer:

2.765 × × 10³ moles of O₂

Explanation:

The chemical equation to produce water from oxygen and hydrogen is;

2H₂ (g) + O₂ (g) = 2H₂O (l)

From the equation above, we see that;

2 moles of H₂O is produced from 1 mole of O₂

Thus; 5.53 × 10³ moles of H₂O will require;

(5.53 x 10³ moles of H₂O × 1 mole of O₂)/2 moles of H₂O = 2.765 × × 10³ moles of O₂

6 0

3 years ago

ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A a

brilliants [131]

Complete Question

You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?

Answer:

The value is $k = 96 %$

Explanation:

From the question we are told that

The percentage of enantiomer A is A = 98%

The percentage of enantiomer B is B = 2%

Generally the enantiomeric excess is mathematically represented as

$k = \frac{A -B}{A+B} * 100$

=> $k = \frac{98 -2}{98+2} * 100$

=> $k = 96 %$

8 0

3 years ago

Magnesium reacts with Lead II Nitrate in a Single Displacement Reaction.<br> Show formula

Leto [7]

Answer:

Mg(s) + Pb(NO3)2 (aq) → Mg(NO3)2 (aq) + Pb(s)

Explanation:

8 0

3 years ago