3Zn(OH)₂ + 2H₃PO₄ → Zn₃(PO₄)₂ + 6H₂O
Explanation:
To balance this equation, we must understand that in every chemical reaction, the number of atoms is usually conserved.
The total number of atoms on the reactant and product sides must be equal and the same.
Zn(OH)₂ + H₃PO₄ → Zn₃(PO₄)₂ + H₂O
We are are going to use simple, solvable algebraic equations to balance this;
aZn(OH)₂ + bH₃PO₄ → cZn₃(PO₄)₂ + dH₂O
a, b,c and d are the number of coefficient that will balance this equation:
Conserving Zn ; a = 3c
O: 2a + 4b = 8c + d
H: 2a + 3b = 2d
P: b = 2c
let c = 1;
a = 3
b = 2
solving for d;
2d = 2(3) + 3(2)
d = 6
3Zn(OH)₂ + 2H₃PO₄ → Zn₃(PO₄)₂ + 6H₂O
learn more:
Balanced equation brainly.com/question/2612756
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I believe the answer is excess reactant?
Boyle's law is a gas law, stating that the pressure and volume of a gas have an inverse relationship, when temperature is held constant i.e PV = constant. Therefore, P1V1 = P2V2--(i) ( P1 = initial pressure, P2= final pressure, V1= initial volume, V2= final volume). P1=930 torr, P2= 970 torr, V1= 95 ml, V2=?.
Put these values in equation (i),
930 torr x 95 ml = 970 torr x V2. Therefore, V2 = 91.08 ml.
