C=Q/U
Q=0,003C
U=30V
C=0,003/30=0,0001F=0,1mF
Answer:
Thus, the change in the weight of the person is 1.6N , option c is correct.
Explanation:
The correct terms to fill in the blanks are solid and gas. The strongest interparticle attractions exist between particles of a solid and the weakest interparticle attractions exist between particles of gas. In a solid substance, the atoms are very close to each other and collision frequency is very high, Thus, attraction between particles is high. For a gas, the molecules are very far from each other to the point that they do not collide. Collision frequency is very small for a gas leading to a weak attraction between particles. An intermediate phase of these two is called the liquid phase, where the particles are far apart but not that far where collisions are more likely to happen.
Answer:
i. The radius 'r' of the electron's path is 4.23 × m.
ii. The frequency 'f' of the motion is 455.44 KHz.
Explanation:
The radius 'r' of the electron's path is called a gyroradius. Gyroradius is the radius of the circular motion of a charged particle in the presence of a uniform magnetic field.
r =
Where: B is the strength magnetic field, q is the charge, v is its velocity and m is the mass of the particle.
From the question, B = 1.63 × T, v = 121 m/s, Θ = (since it enters perpendicularly to the field), q = e = 1.6 × C and m = 9.11 × Kg.
Thus,
r = ÷ sinΘ
But, sinΘ = sin = 1.
So that;
r =
= (9.11 × × 121) ÷ (1.6 × × 1.63 × )
= 1.10231 × ÷ 2.608 ×
= 4.2266 ×
= 4.23 × m
The radius 'r' of the electron's path is 4.23 × m.
B. The frequency 'f' of the motion is called cyclotron frequency;
f =
= (1.6 × × 1.63 × ) ÷ (2 × × 9.11 × )
= 2.608 × ÷ 5.7263 ×
= 455442.4323
f = 455.44 KHz
The frequency 'f' of the motion is 455.44 KHz.
<h3><u>Answer</u>;</h3>
1600 years
<h3><u>Explanation</u>;</h3>
- Half life is the time taken for a radioactive isotope to decay by half of its original amount.
- We can use the formula; N = O × (1/2)^n ; where N is the new mass, O is the original amount and n is the number of half lives.
- A sample of radium-226 takes 3200 years to decay to 1/4 of its original amount.
Therefore;
<em>1/4 = 1 × (1/2)^n</em>
<em>1/4 = (1/2)^n </em>
<em>n = 2 </em>
Thus; <em>3200 years is equivalent to 2 half lives.</em>
<em>Hence, the half life of radium-226 is 1600 years</em>