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choli [55]
2 years ago
10

A pendulum is timed, first for 20 swings and then for

Physics
1 answer:
wlad13 [49]2 years ago
3 0

w =  \frac{t(50) - t(20)}{50 - 20}  =  \frac{43.2 - 17.4}{50 - 20}

w =  \frac{25.8}{30}  = 0.86 \: sec \: per \: swing

The results may differ due to resistive forces that may be affecting the system by decelerating it or any other external forces that might accelerate it a bit.Or the timing could be a little inaccurate.

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The vertebral region is _________ to the scapular region.
Lisa [10]

Answer:

<em>The answer is medial!</em>

Explanation:

<em>The vertebral region is </em><u><em>medial</em></u><em> to the scapula.</em>

<em>Hope This Helps!</em>

<em>-</em><u><em>Justin:)</em></u>

7 0
2 years ago
a 300-kg crate is placed on a adjustable incline plane. as one end of the incline is raised, the crate begins to move downward.
denis-greek [22]

Answer:

A 300-kg crate is placed on a adjustable incline plane. as one end of the incline is raised, the crate begins to move downward. if the crate slides down the plane with the acceleration of .70 m/s2 , when the incline is 25 degrees, what is the coefficient of kinetic friction between ramp and crate?

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3 years ago
Find the wavelength of radio waves of frequency 200kHz
Gala2k [10]
\lambda = \frac{c}{f}
λ - wavelength, c - the speed of light, f - frequency

f=200 \ kHz= 200 000 \ Hz \\ \\&#10;\lambda=\frac{300 000 \ [\frac{km}{s}]}{200 000 \ [Hz]}=\frac{3}{2}=1.5 \ [km]

The wavelength of these waves is 1.5 km.
3 0
3 years ago
Read 2 more answers
Photoelectrons are observed when a metal is illuminated by light with a wavelength less than 383 nm. What is the metal's work fu
Ulleksa [173]

Answer:

Work function of the metal is 3.24 eV.                                    

Explanation:

It is given that,

Wavelength, \lambda=383\times 10^{-9}\ m

Let W is the work function of the metal. It is given by using Einstein's photoelectric effect equation. It is given by :

W=\dfrac{hc}{\lambda}

W=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{383\times 10^{-9}}

W=5.193\times 10^{-19}\ J

Since, 1\ eV=1.6\times 10^{-19}\ J

So, W = 3.24 eV

So, the work function of the metal is 3.24 eV. Hence, this is the required solution.

3 0
3 years ago
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xxTIMURxx [149]

Answer:

B 0j

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