In the sport of volleyball a server is in the "back left position" for standard rules.
Hope I helped,
-CSX :)
You measure the distance between crest and crest or trough and trough
In collision type of problems since momentum is always conserved
we can say

So here along with this equation we also required one more equation for the restitution coefficient

so above two equations are required to find the velocity after collision
here the change in velocity occurs due to the contact force while they contact in each other
so this is the impulse of collision while they are in contact with each other while in collision which changes the velocity of two colliding objects
Answer:
Velocity = 20.3 [m/s]
Explanation:
This is a typical problem of energy conservation, where potential energy is converted to kinetic energy. We must first find the potential energy. In this way, we will choose as a reference point or point where the potential energy is zero when the carrriage rolls down 21 [m] from the top of the hill.
![E_{p} =m*g*h\\ where:\\m = mass = 25[kg]\\g = gravity = 9.81 [m/s^2]\\h = elevation = 21 [m]\\E_{p} =potential energy [J]\\E_{p} =25*9.81*21=5150[J]](https://tex.z-dn.net/?f=E_%7Bp%7D%20%3Dm%2Ag%2Ah%5C%5C%20where%3A%5C%5Cm%20%3D%20mass%20%3D%2025%5Bkg%5D%5C%5Cg%20%3D%20gravity%20%3D%209.81%20%5Bm%2Fs%5E2%5D%5C%5Ch%20%3D%20elevation%20%3D%2021%20%5Bm%5D%5C%5CE_%7Bp%7D%20%3Dpotential%20energy%20%5BJ%5D%5C%5CE_%7Bp%7D%20%3D25%2A9.81%2A21%3D5150%5BJ%5D)
Now this will be the same energy transformed into kinetic energy, therefore:
![E_{p}=E_{k} = 5150[J]\\E_{k} =0.5*m*v^{2} \\where:\\v=velocity [m/s]\\v=\sqrt{\frac{E_{k}}{0.5*25} } \\v=20.3[m/s]](https://tex.z-dn.net/?f=E_%7Bp%7D%3DE_%7Bk%7D%20%3D%205150%5BJ%5D%5C%5CE_%7Bk%7D%20%3D0.5%2Am%2Av%5E%7B2%7D%20%5C%5Cwhere%3A%5C%5Cv%3Dvelocity%20%5Bm%2Fs%5D%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7BE_%7Bk%7D%7D%7B0.5%2A25%7D%20%7D%20%5C%5Cv%3D20.3%5Bm%2Fs%5D)
The definition of motion is the action or process of moving or being moved.