All categories

2 years ago

Please help me find x

Mathematics

2 answers:

Pavel [41]2 years ago

8 0

The answer for this will be 2

Viktor [21]2 years ago

7 0

Answer:

x = 48 degrees

Step-by-step explanation:

This is an isosceles triangle because two sides of the triangle are marked equally

so it means the two bottom corners of the triangle (the 66 degrees and the bottom angle on the right) are equal (1)

The theorem says that all the angles in a triangle adds up to 180 degrees (2)

(1), (2) =) 180 - 66*2 = 48 degrees

x = 48 degrees

I hope this help^^ Sr if I make any mistake in the grammar

You might be interested in

Can you do the “Describe fully” question please

Black_prince [1.1K]

Answer:

no sorry because I am week in maths

7 0

2 years ago

Brandi's new balance on her credit card statement was $256.38.

Amiraneli [1.4K]

Answer:

$38.46

Step-by-step explanation:

Minimum payment = 15% of balance

Balance = $256.38

Therefore

15% of $256.38

Change 15% to decimal

15% /100% x $256.38

0.15 x $256.38

$38.46

Her minimum payment is $38.46

6 0

2 years ago

I need help ASAP for my homework

bogdanovich [222]

Answer:

slope of line ax + by = c is -a/b

so, slope of 7x +2y =5 is -7/2

3 0

2 years ago

Read 2 more answers

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

3 years ago

An ostrich can run at a rate of 50 miles in 60 minutes.At this rate,how long would it take an ostrich to run 15 miles?

just olya [345]

If an ostrich can run 50 miles in one hour then he can run 12.5 miles in 15 minutes. 15 minutes is 1/4 of an hour. Multiply 50 by 0.25 = 15.

3 0

3 years ago