Given:
The terminal point of is (1,0).
To find:
The value of .
Solution:
If the terminal point of is (x,y), then
It is given that the terminal point of is (1,0).
Here, x-coordinate is 1 and the y-coordinate is 0. Using the above formula, we get
Therefore, the value of is 0.
Answers:
a = -6/37
b = -1/37
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Explanation:
Let's start things off by computing the derivatives we'll need
Apply substitution to get
I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.
The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero
a-6b = 0
a = 6b
At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)
-6a -b = 1
-6(6b) - b = 1 .... plug in a = 6b
-36b - b = 1
-37b = 1
b = -1/37
Use this to find 'a'
a = 6b
a = 6(-1/37)
a = -6/37