All categories

3 years ago

A car factory can produce 362 cars every 8 hours. How many cars could the factory produce in 44 hours?

Mathematics

2 answers:

aev [14]3 years ago

7 0

Answer:

159,280 i think hope this helps i did alot of research and u coulddo this

Step-by-step explanation:

362 times 8 times 44 i tied hard

Leto [7]3 years ago

5 0

Answer:

1991

Step-by-step explanation:

I divided 44 by 8 to how many times 362 cars would be made. I got 5.5 and then multiplied that by 362 to see that 1991 cars will be produced.

You might be interested in

I need help Please!

Pachacha [2.7K]

Answer:

Step-by-step explanation:

7 0

3 years ago

How do you graph the function g(x)

Verizon [17]

Lightly draw a vertical line at -3 (x= -3 is the divider) on the left side graph x + 1, on the right side graph 1/2x + 2.
because these equations don't match up at the -3 coordinate, you have to draw an open (not colored in) circle at the beginning at the 1/2x-2 equation

6 0

3 years ago

Paul bags of raisin bars in a pan shaped like a rectangle or prism the volume of the pan is 252 in.³ the length of the pants 12

e-lub [12.9K]

Answer:

The height of the pan is 2 inches.

Step-by-step explanation:

Given : Paul bags of raisin bars in a pan shaped like a rectangle or prism the volume of the pan is 252 in.³ the length of the pants 12 inches and it's with is $10\frac{1}{2}$ inches.

To find : What is the height of the pan ?

Solution :

The volume of a rectangle or prism is

$V=l\times w\times h$

Where, l=12 inches is the length

$w=10\frac{1}{2}$ inches is the width

V=252 in.³ is the volume

h is the height

Substitute the value,

$252=12\times 10\frac{1}{2}\times h$

$252=12\times \frac{21}{2}\times h$

$h=\frac{252\times 2}{12\times 21}$

$h=2$

Therefore, the height of the pan is 2 inches.

7 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Select the correct answer. Which statement about an electromagnet is true? A. It doesn’t function without a source of current. B

zubka84 [21]

Answer:I’m going to say it’s A I apologize if it’s wrong

Step-by-step explanation:

Magnets are magnetic fields that compares together when attracted close to one another so that’s Why I’m choosing A because it’s close to what I think

3 0

4 years ago