<span>Since at STP, the molar volume is 22.4 L, all of these containers have one mole of gas. The one with the highest atomic or molecular weight is the heaviest: :
A) H2 - 2 g/mole
B) N2 - 28 g/mole
C) O2 - 32 g/mole
D) CO2 - 44 g/mole
E)He - 4 g/mole
Ans will CO2 - 44 g/mole with the highest atomic or molecular weight is the heaviest.</span>
a plant that has flowers and fruits
Answer:
24.32 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A (Mg–24):
Mass of A = 24 amu
Abundance (A%) = 79%
Isotope B (Mg–25):
Mass of B = 25 amu
Abundance (B%) = 10%
Isotope C (Mg–26):
Mass of C = 26 amu
Abundance (C%) = 11%
Average atomic mass of Mg =?
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
= [(24 × 79)/100] + [(25 × 10)/100] + [(26 × 11)/100]
= 18.96 + 2.5 + 2.86
= 24.32 amu
Thus, the average atomic mass of Mg is 24.32 amu
Answer is: <span>A. 18.02 g/mol.
At standard temperature and pressure 1 mol of gas occupied 22.4 liters:
V(H</span>₂O) = 22.4 L; volume of water.
Vm = 22.4 L/mol; molar volume at STP.
n(H₂O) = V ÷ Vm.
n(H₂O) = 22.4 L ÷ 22.4 L/mol.
n(H₂O) = 1 mol; amount of substance (water).
M(H₂O) = Ar(O) + 2Ar(H) · g/mol.
M(H₂O) = 16 + 2 ·1.01 · g/mol.
M(H₂O) = 18.02 g/mol; molar mass of water.
Answer:
option e = 1.99 × 10⁻⁶ m
Explanation:
Given data:
Mass of electron = 9.11 × 10⁻²⁸ g or 9.11 × 10⁻³¹ Kg
Velocity = 3.66 × 100 m/s
Wavelength = ?
Solution:
Formula:
λ = h / m. v
λ = wavelength
h = planck's constant
m = mass
v = velocity
Now we will put the values in equation
λ = h / m. v
λ = 6.63 × 10⁻³⁴ Kg. m²/s / 3.66 × 100 m/s . 9.11 × 10⁻³¹ Kg
λ = 6.63 × 10⁻³⁴ Kg. m²/s / 3334.26 × 10⁻³¹ Kg .m/s
λ = 1.99 × 10⁻⁶ m