Hello!
The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.
We have the following data:
mo (initial mass) = 53.3 mg
m (final mass after time T) = ? (in mg)
x (number of periods elapsed) = ?
P (Half-life) = 10.0 minutes
T (Elapsed time for sample reduction) = 25.9 minutes
Let's find the number of periods elapsed (x), let us see:
![T = x*P](https://tex.z-dn.net/?f=%20T%20%3D%20x%2AP%20)
![25.9 = x*10.0](https://tex.z-dn.net/?f=%2025.9%20%3D%20x%2A10.0%20)
![25.9 = 10.0\:x](https://tex.z-dn.net/?f=%2025.9%20%3D%2010.0%5C%3Ax%20)
![10.0\:x = 25.9](https://tex.z-dn.net/?f=%2010.0%5C%3Ax%20%3D%2025.9%20)
![x = \dfrac{25.9}{10.0}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B25.9%7D%7B10.0%7D%20%20)
![\boxed{x = 2.59}](https://tex.z-dn.net/?f=%20%5Cboxed%7Bx%20%3D%202.59%7D%20)
Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:
![m = \dfrac{m_o}{2^x}](https://tex.z-dn.net/?f=%20m%20%3D%20%20%5Cdfrac%7Bm_o%7D%7B2%5Ex%7D%20%20)
![m = \dfrac{53.3}{2^{2.59}}](https://tex.z-dn.net/?f=%20m%20%3D%20%20%5Cdfrac%7B53.3%7D%7B2%5E%7B2.59%7D%7D%20%20)
![m \approx \dfrac{53.3}{6.021}](https://tex.z-dn.net/?f=%20m%20%5Capprox%20%5Cdfrac%7B53.3%7D%7B6.021%7D%20%20)
![\boxed{\boxed{m \approx 8.85\:mg}}\end{array}}\qquad\checkmark](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7Bm%20%5Capprox%208.85%5C%3Amg%7D%7D%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20)
I Hope this helps, greetings ... DexteR! =)
When the balanced equation for this reaction is:
2Fe + 3H2O → Fe2O3 + 3H2
and according to the vapour pressure formula:
PV= nRT
when we have P is the vapor pressure of H2O= 0.121 atm
and V is the volume of H2O = 4.5 L
and T in Kelvin = 52.5 +273 = 325.5 K
R= 0.08205 atm-L/g mol-K
So we can get n H2O
So, by substitution:
n H2O = PV/RT
= (0.121*4.5)/(0.08205 * 325.5) = 0.02038 gmol
n Fe2O3 = 0.02038 * (1Fe2O3/ 3H2O) = 0.00679 gmol
Note: we get (1FeO3/3H2O) ratio from the balanced equation.
we can get the Mass of Fe2O3 from this formula:
Mass = number of moles * molecular weight
when we have a molecular weight of Fe2O3 = 159.7
= 0.00679 * 159.7 = 1.084 g
∴ 1.084 gm of Fe2O3 will produced
Butyl Alcohol on reaction with Oxygen produces Butyric Acid and Water.
The Balance Chemical equation is as follow,
C₄H₉OH + O₂ → C₄H₇O₂H + H₂O
Result: The equation given in statement is already balanced.
Answer:
16.7%
Explanation:
40 ml of salt water + 200 ml of solution = 240 ml
40/240 = 4/24 = 1/6=16.7%