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dlinn [17]
3 years ago
9

To calculate the number of atoms present in 2.0 mol of an element you would:

Chemistry
1 answer:
Andrews [41]3 years ago
4 0
<span>In order to figure out the number of atoms that are present in 2.0 mol of an element, you would multiply Avogadro's number of atoms per mole by 2.0 mole. Avogadro’s is the number of units in one mole of a substance equal to 6.022140857 × 1023.</span>
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Activity
Monica [59]

Answer:

The mass of a pure substance represents a specific number of pure substance 'molecules', as defined by molecular weight. The relative atomic mass (atomic weight) in grams/mole (g/mol) is the molar mass of a substance, which means it is the mass of one mole of that substance.

Explanation:

Hope this helps :)

8 0
3 years ago
How many liters of methane gas (CH4) need to be combusted to produce 8.5 liters of water vapor, if all measurements are taken at
zimovet [89]
8.5L H2O (1 mol H2O/22.4L)=.37946 mol H2O
.3796 mol H2O(1 mol CH4/2 mol H2O)=.18973 mol CH4
.18973 mol CH4(22.4L/1mol CH4)=4.25L CH4 gas
6 0
3 years ago
Calculate the mass in grams in nine molecules of CH3COOH? Please show how you got your answer.
WINSTONCH [101]
M CH₃COOH: 12u×2 + 1u×4 + 16u×2 =<u> 60u</u>

m 9CH₃COOH: 60u×9 = <u>540u</u>

<em>(1u ≈ 1,66·10⁻²⁴g)</em>
-----------------------------
1u ------- <span>1,66·10⁻²⁴g
540u ---- X
X = 540</span>×<span>1,66·10⁻²⁴g
<u>X = 896,4</u></span><span><u>·10⁻²⁴g


</u>
</span>
7 0
3 years ago
If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised
alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}

Solving for V₂ , we get:

<u>V₂ = 15.04 mL</u>

3 0
3 years ago
What is the net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH?
Lesechka [4]
<span>The net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH is </span>the solid AlOH3  formed.
7 0
3 years ago
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