I found an image that corresponds to the above question.
The shape was a rectangle. Its width is 7 units, its length is x.
The shaded area of the rectangle forms a trapezoid.
Area of a trapezoid = [(a+b)/2] * h
63 sq. units = (7+x)/2 * 7
63/7 = (7+x)/2
9 = (7+x)/2
9*2 = 7 + x
18 = 7 + x
18 - 7 = x
11 = x
The value of x is 11 units. It is the length of the rectangle.
Area of the trapezoid = (a+b)/2 * h
63 = (7+11)/2 * 7
63 = 18/2 * 7
63 = 9 * 7
63 = 63
7 + 5 + 2 = 14 because seven plus five is twelve, twelve plus two is fourteen.
Answer:
y=1/2x-7
Step-by-step explanation:
u19=-71.74
Step-by-step explanation:
u5=a+4d=-3.7....(1)
u15=a+14d=-52.3....(2)
-10d=48.6
d=-48.6/-10
d=-4.86
Substitute-4.86 into....(1)
u5=a+4(-4.86)=-3.7
a+(-19.44)=-4.7
a=-3.7-(-19.44)
a=15.74
19term=a+18d=?
=15.74+18(-4.86)
=15.74+(-87.48)
19th term =-71.74
Answer:
I think the answer is 10 full 6Kg boxes
my first answer if you saw it was miscalculated, sorry.