Using two different instruments I measured the length of my foot to be 27 centimeters and 27.00 centimeters. Explain the differe
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<u>Answer:</u> The Van't Hoff factor for KCl is 1.74
<u>Explanation:</u>
We are given:
Molality of solution = 1 m
This means that 1 mole of a solute is present in 1 kg of solvent (water) or 1000 grams of water
To calculate the number of moles, we use the equation:
Given mass of water = 1000 g
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
Mole fraction of a substance is given by:
Moles of solute = 1 moles
Total moles = [1 + 55.56] = 56.56 moles
Putting values in above equation, we get:
The equation used to calculate relative lowering of vapor pressure follows:
where,
= relative lowering in vapor pressure = 0.734 mmHg
i = Van't Hoff factor = ?
= mole fraction of solute = 0.0177
= vapor pressure of pure water = 23.76 torr
Putting values in above equation, we get:
Hence, the Van't Hoff factor for KCl is 1.74
The mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
From a detailed understanding of Avogadro's hypothesis, we understood 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of I₂ also 6.02×10²³ molecules i.e
<h3>6.02×10²³ molecules = 1 mole of I₂</h3>Recall:
1 mole of I₂ = 2 × 127 = 254 g
Thus,
<h3>6.02×10²³ molecules = 254 g of I₂</h3>With the above information, we can obtain the mass of I₂ that contains 2.57×10²⁵ molecules. This is illustrated below:
6.02×10²³ molecules = 254 g of I₂
Therefore,
2.57×10²⁵ molecules =
Thus, the mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
Learn more: brainly.com/question/24848191
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Explanation
The orbital quantum number of an atomic subshell determines the maximum number of electrons it can contain. For example:
- Each
orbital
holds up to
electrons
- Each
orbital
holds up to
electrons
- Each
orbital
holds up to
electrons
The atom in question here contains four fully-occupied orbitals, two fully-occupied
orbitals along with
electrons in a partially-occupied
orbital. It thus contains