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3 years ago

Classify the items based on whether they are or are not matter. toothpaste, happiness, gasoline, sound, bacteria, cell

2 answers:

8 0

They are all matter, in fact, anything that takes up space is matter because atoms are building blocks of matter, and everything is made up of atoms.

kirill115 [55]3 years ago

8 0

Answer:

Matter : toothpaste, gasoline, bacteria, cell

Non matter: happiness, sound.

Explanation:

Matter is a substance which occupies space.

For example, sugar, chair, water, ice, etc.

Non matter is the substance which does not occupy space.

For example, anger, cold, hot, etc.

In the given data,

Matter : toothpaste, gasoline, bacteria, cell

Non matter: happiness, sound.

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Answer:

ΔH = -45.1872 kJ , where negative sign signifies heat loss.

Q = ΔH = -45.1872 kJ , where negative sign signifies heat loss.

S system = -0.141 kJ/K

S surroundings = 0.1536 kJ/K

S universe = -0.141 kJ/K + 0.1536 kJ/K = 0.0126 kJ/K

Explanation:

Given:

Cp = 4. 184 J/(mole. K)

T₁ = 75 ⁰C

T₂ = 21 ⁰C

Mass of water = 200 g = 0.2 kg

Since,

$\Delta H=m\times C\times (T_f-T_i)$

ΔH = 0.2*4.184*(21-75) kJ

ΔH = -45.1872 kJ , where negative sign signifies heat loss.

Since the process is at constant pressure

Q = ΔH = -45.1872 kJ , where negative sign signifies heat loss.

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

T₁ = 75 ⁰C = 348 .15 K

T₂ = 21 ⁰C = 294.15 K

The entropy of the water is given by:

S = m×Cp×ln(T₂ /T₁)

S = 0.2*4.184*ln(294.15/348.15)

S system = -0.141 kJ/K

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The entropy change of surroundings is

S surr = dQ/T₂ = 45.1872/294 .15

S surr = 0.1536 kJ/K

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