Answer:
2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂
2Na + MgCl₂ → 2NaCl + Mg
Explanation:
A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation
Among the given chemical reactions, we have;
2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂
In the above reaction;
The number of phosphorus, P, on either side of the equation = 2
The number of bromine atoms, Br, on either side of the equation = 6
The number of chlorine atoms, Cl, on either side of the equation = 6
Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced
The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg
In the above reaction, there are two sodium atoms, Na, one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced
Thermal energy that flows between objects due to a difference in temperature is heat.
Answer:
Option C
Explanation:
From the question we are told that:
Mass 
Radius 
Time 
Generally the equation for Tension is mathematically given by
Therefore
, toward the center of the circle
Option C
Answer:
New Resistance = 247.5 ohm
Explanation:
Resistance = resistivity * length / area
Since resistivity for the material is constant, resistance is directly proportional to (length/area).
This means that if (length/area) decreases or increases by any ratio, then resistance will increase or decrease by the same ratio.
So let's find the change in length/area
New length = 0.25 old length
New area = (1/9) old area (This is because area equation contains a square of the diameter. if diameter decreases by 1/3, area decreases by (1/3)^2 )
So we now get length /area:
New length / new area = ( 0.25 old length) / (1/9 of old area)
New length / new area = 9*0.25 (old length / old area)
New length / new area = 2.25 (old length / old area)
To get the new resistance, we simply multiply it by the ratio we just found.
This equals:
110 * 2.25 = 247.5 ohm
The answer is B, because all energy is released at once in static electricity.
There’s a quizlet that mentions these questions, if you are having trouble. I’d suggest to give them a look.
