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3 years ago

9

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2 answers:

ehidna [41]3 years ago

5 0

E. Each ticket costs $15 and Gina has to buy 5 tickets for her and her friends. $w is the total cost of 5 tickets that cost $15 each.

poizon [28]3 years ago

3 0

Each ticket cost $15

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-(18+4x)=8 hope you can help

Step2247 [10]

-1(18+4x)=8
Then you distribute
-18-4x=8
-4x=26
X= -6.5

4 0

3 years ago

Read 2 more answers

The perimeter of a semicircle is 5.14 feet. What is the semicircle’s area?

hammer [34]

$\bf \textit{circumference of a semi-circle}\\\\
C=\pi r\qquad 
\begin{cases}
r=radius\\
-----\\
C=5.14
\end{cases}\implies 5.14=\pi r\implies \boxed{\cfrac{5.14}{\pi }=r}\\\\
-------------------------------\\\\
\textit{area of a semi-circle}\\\\
A=\cfrac{\pi r^2}{2} \implies A=\cfrac{\pi }{2}r^2\implies A=\cfrac{\pi }{2}\left( \boxed{\cfrac{5.14}{\pi }} \right)^2
\\\\\\
A=\cfrac{\pi }{2}\implies \cfrac{5.14^2}{\pi ^2}\implies A=\cfrac{26.4196}{2\pi }\implies A=\cfrac{13.2098}{\pi }$

5 0

2 years ago

2x-7=117 what is the value of x

Tcecarenko [31]

$2x - 7 = 117$

Add 7 to both sides

$7 + 2x - 7 = 117 + 7$

At the left hand side 7 will cancel 7

At the right hand side 7 will add up

$2x = 124$

Divide through by 2

$x = \frac{124}{2}$

simplify the fraction

$x = 62$

4 0

2 years ago

Prove the identity (n-5)^2 - (6n-35)=(n-10)(n-6)

elena-14-01-66 [18.8K]

Answer:

(n-5)^2 - (6n-35)=(n-10)(n-6)

-----------

n²-10n+25-6n+35 =
n²-16+60 = n²- 10n - 6n + 60 =
n(n-10) - 6(n-10) =
(n-10)(n-6)

7 0

3 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

3 0

3 years ago