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3 years ago

:

2 answers:

5 0

E. Each ticket costs $15 and Gina has to buy 5 tickets for her and her friends. $w is the total cost of 5 tickets that cost $15 each.

poizon [28]3 years ago

3 0

Each ticket cost $15

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Sklyer has 15 less than twice as many customers as when she started selling newspapers. She now has 155 customers. How many did

arlik [135]

155 = 2x -15
170 = 2x
85 = x

She had 85 when she first started.

8 0

3 years ago

Read 2 more answers

(-5, -1) and (1,9) Answer:

xxMikexx [17]

Answer:

m = 5/3

Step-by-step explanation:

7 0

3 years ago

The point C(2,3) is translated along a vector that is parallel to the line y=3x-2. The translation vector has magnitude square r

qaws [65]

Step-by-step explanation:

The translation vector v can be resolved into its x and y components, where x² + y² = 10 (Pythagoras' Theorem) and y = 3x

(parallel to y = 3x - 2, slope = 3).

We have x² + (3x)² = 10,

=> x² + 9x² = 10, 10x² = 10, x = 1 or x = -1.

When x = 1, y = 3. When x = -1, y = -3.

Therefore 2 possible translation vectors

are (1, 3) or (-1, -3).

First new C' = (2 + (1), 3 + (3)) = (3, 6).

Second new C'= (2 + (-1), 3 + (-3)) = (1, 0).

The possible images are (3, 6) and (1, 0).

4 0

3 years ago

ASAP PLS HELP ILL GIVE U A COOKIE

Dvinal [7]

Answer:

x = 11

Step-by-step explanation:

7 0

3 years ago

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Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (

Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

The correct equation is

$y+1=\sqrt{-2y-3}$

Solve for y

squared both sides

$(y+1)^2=(-2y-3)$

$(y^2+2y+1)=(-2y-3)$

$y^2+2y+1+2y+3=0$

$y^2+4y+4=0$

$(y+2)(y+2)=0$

$y=-2$

Verify

substitute the value of y in the original expression

$-2+1=\sqrt{-2(-2)-3}$

$-1=1$ ----> is not true

therefore

There are no true solutions to the equation.

4 0

3 years ago