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2 years ago

What would my final balance be if I put $650 in the bank for 60 months with an interest rate of 6%?

1 answer:

5 0

It depends on the terms of the account.

If interest is compounded annually, 650*1.06^5 ≈ 869.85 . . . . dollars.
If interest is compounded quarterly, 650*1.015^20 ≈ 875.46 . . dollars.
If interest is compounded monthly, 650*1.005^60 ≈ 876.75 . . .dollars.

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The interval for which is non real is

scZoUnD [109]

Answer:

Step-by-step explanation:

it is non real if x²-36<0

x²<36

|x|<6

so -6<x<6

7 0

2 years ago

Write the equation of the line, in point-slope form. Identify (x1, y1) as the point (1, 2). Use the box provided or the upload o

AlexFokin [52]

We are given with the coordinates of one of the points of a line which is
(1,2)
In order to generate an equation of a line, we need at least one other point or the slope of the line. If we are given with the slope of line, we can use the point slope form which is
y - y1 = m (x - x1)
substituting
y - 2 = m(x - 1)

8 0

2 years ago

Mala is y years old. Her sister is 4 years older than mala . Write expréssion in simplest form that represents the sum of ages o

Evgen [1.6K]

Answer:

$2(y+2)$

Step-by-step explanation:

Let

y --->Mala's age

x---> sister's age

we know that

$x=y+4$ ---> equation A

The sum of ages of the sisters is

$x+y$

substitute equation A in the expression of the sum of ages

$(y+4)+y=2y+4$

simplify

$2(y+2)$

8 0

3 years ago

Rotate figure 180 degrees clock wise about point (-2,3)

disa [49]

2,-3 is the answer if it's just a point

4 0

3 years ago

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

2 years ago