Answer:
a) 29
b) 0
c) 7
d) 3/8
Step-by-step explanation:
Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.
If the result is negative, you add the clock hours.
a) 21 - 33 = -12 , so -12 + 41 = 29
b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.
c) 11+19 = 30, 30 - 23 = 7
d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.
Answer:
nope i need more points lol
Step-by-step explanation:
Answer:
C. (3x)^2 - (2)^2
Step-by-step explanation:
Each of the two terms is a perfect square, so the factorization is that of the difference of squares. Rewriting the expression to ...
(3x)^2 - (2)^2
highlights the squares being differenced.
__
We know the factoring of the difference of squares is ...
a^2 -b^2 = (a -b)(a +b)
so the above-suggested rewrite is useful for identifying 'a' and 'b'.
Answer:
Step-by-step explanation:
6*[4-(42-63)]=
6*[4-(-21)]=
6*[4+21]=
6*25=150.
6*[4-9÷3]=
6*[4-27]=
6*(-23)=-138.
6*[4-3]=
6*1=6.
Answer: <u><em>I think that the answer should be 2.4</em></u>
<u><em /></u>
Step-by-step explanation: <em><u>The reason why is because they did 2 the 2.2 so their going up by twos I belive making the answer 2.4.</u></em>
