9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
5^2 + 12^2 = c^2
25 + 144 = c^2
169 = c^2
take the square root of both sides
+ - 13 = c
Answer:
land on 3: 36 times
land on 4: 63 times
Step-by-step explanation:
A biased dice is the opposite of a fair dice.
A fair dice has the same probability of landing any of the six numbers: 1/6
The biased dice has different probabilities for its results.
To solve this question, first we need to find the probability of landing a 3.
The sum of all probabilities need to be 1, so:
0.13 + 0.05 + p(3) + 0.21 + 0.19 + 0.3 = 1
p(3) = 1 - 0.88 = 0.12
If we roll the dice 300 times, the expected number of times the dice will land:
on 3: 300 * p(3) = 300 * 0.12 = 36 times
on 4: 300 * p(4) = 300 * 0.21 = 63 times
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