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FinnZ [79.3K]
3 years ago
14

Solve for x 2x+10 divided by 4=y

Mathematics
2 answers:
kogti [31]3 years ago
8 0
Be more specific this makes no sense
Rzqust [24]3 years ago
4 0
(2x + 10)/4 = y
multiply both sides by 4
2x + 10 = 4y
subtract 10 from both sides
2x = 4y - 10
divide both sides by 2
x = (4y - 10)/2 OR x = 2y - 5
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What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in
EastWind [94]

Answer:

6\sqrt{19} \approx 26.153 inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment \mathsf{AG}.

In this diagram (not to scale,) \mathsf{AB} = 26 (length of prism,) \mathsf{AC} = 2 (width of prism,) \mathsf{AE} = 2 (height of prism.)

Pythagorean Theorem can help find the length of \mathsf{AG}, one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment \mathsf{AD}. That's the black dotted line in the diagram. In right triangle \triangle\mathsf{ABD} (second diagram,)

  • Segment \mathsf{AD} is the hypotenuse.
  • One of the legs of \triangle\mathsf{ABD} is \mathsf{AB}. The length of \mathsf{AB} is 26, same as the length of this prism.
  • Segment \mathsf{BD} is the other leg of this triangle. The length of \mathsf{BD} is 2, same as the width of this prism.

Apply the Pythagorean Theorem to right triangle \triangle\mathsf{ABD} to find the length of \mathsf{AB}, the hypotenuse of this triangle:

\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}.

Consider right triangle \triangle \mathsf{ADG} (third diagram.) In this triangle,

  • Segment \mathsf{AG} is the hypotenuse, while
  • \mathsf{AD} and \mathsf{DG} are the two legs.

\mathsf{AD} = \sqrt{26^2 + 2^2}. The length of segment \mathsf{DG} is the same as the height of the rectangular prism, 2 (inches.) Apply the Pythagorean Theorem to right triangle \triangle \mathsf{ADG} to find the length of the hypotenuse \mathsf{AG}:

\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}.

Hence, the length of the longest line segment in this prism is 6\sqrt{19} \approx 26.153 inches.

5 0
3 years ago
Plz help on homework
8_murik_8 [283]

Answer:

see attached

Step-by-step explanation:

As you know, dividing by a fraction is the same as multiplying by that fraction's inverse (or reciprocal). Any whole number is equivalent to the fraction that is that whole number divided by 1. (For example, 4 = 4/1.)

4 0
3 years ago
In Lesson 1.4, you learned about a water footprint. Part of a person's water footprint is the water used for cleaning. In this q
otez555 [7]

Answer: a) $26.55/year

b) $64.13/year

Step-by-step explanation:

a) <u>$7.64</u>   .   <u>1 ft³</u>     .     <u>50 gal</u> .   <u>1 load </u>   .  <u>52 week</u>   = $<u>26.55</u>

    100 ft³   7.48 gal      1 load      1 week       1 year           year

The total cost per year is $26.55

b)<u>$7.64</u>   .   <u>1 ft³</u>     .     <u>17.2 gal</u>      .   <u>1 shower </u>   .  <u>365 days</u>   = <u>$64.13</u>

    100 ft³   7.48 gal      1 shower         1 day            1 year            year

The total cost per year is $64.13

7 0
3 years ago
The sum of two numbers is odd. Can the quotient of the two numbers be an odd number?
Natalka [10]

Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

4 0
3 years ago
TRUE or FALSE. In a randomly generated list of numbers from 0 to 5, the chance that each number can occur is 1/5 .
mel-nik [20]
Thank you for posting your question here at brainly. Feel free to ask more questions.  

<span>The best and most correct answer among the choices provided by the question is FALSE.</span><span>       
    </span><span>
<span>Hope my answer would be a great help for you.</span></span>
3 0
3 years ago
Read 2 more answers
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