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scoundrel [369]
4 years ago
5

7 th grade math pls help me ! 4=x/4

Mathematics
2 answers:
egoroff_w [7]4 years ago
7 0

Answer:x=16

Step-by-step explanation:

Step 1: Multiply both sides by 4.

4=x/4

(4)*(4)=(x/4)*(4)

16=x

Step 2: Flip the equation.

X=16

Hope this helps:)

forsale [732]4 years ago
5 0

Answer:

x=16

Step-by-step explanation:

multiply 4 on both sides

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Read 2 more answers
Suppose the life of a particular brand of calculator battery is approximately normally distributed with a mean of 75 hours and a
shepuryov [24]

Answer:

a) P(X

And we can find this probability using the normal standard table or excel:

P(z

b) P(X>77)=P(\frac{X-\mu}{\sigma}>\frac{77-\mu}{\sigma})=P(Z>\frac{77-75}{10})=P(z>0.2)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.2)=1-P(Z

c) z = \frac{70-75}{\frac{10}{\sqrt{16}}}= -2

z = \frac{80-75}{\frac{10}{\sqrt{16}}}= 2

And we can find this probability with this difference:

P(-2

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the life of a particular brand of a population, and for this case we know the distribution for X is given by:

X \sim N(75,10)  

Where \mu=75 and \sigma=10

Part a

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Part b

P(X>77)=P(\frac{X-\mu}{\sigma}>\frac{77-\mu}{\sigma})=P(Z>\frac{77-75}{10})=P(z>0.2)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.2)=1-P(Z

Part c

For this case we select a sample size of n =16. and we want this probability:

P(70 < \bar X

We know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we can find the z scores for the limits like this:

z = \frac{70-75}{\frac{10}{\sqrt{16}}}= -2

z = \frac{80-75}{\frac{10}{\sqrt{16}}}= 2

And we can find this probability with this difference:

P(-2

6 0
4 years ago
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